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2 years ago

What is the molarity of a 785 ml solution that contains 6.5 moles of HCI

Chemistry

2 answers:

RUDIKE [14]2 years ago

8 0

Molarity=no. of moles/volume of soln in liter

=6.5/(785/1000)

=8.28M of HCl

Finger [1]2 years ago

5 0

13/1570

equation for molarity = moles of solute / litres of solution

Molarity = 6.5/785=13/1570

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What is the most abundant greenhouse gas released through human activities? a. methane b. nitrous oxide c. carbon dioxide d. sul

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2 years ago

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How many molecules are in 0.55 moles of Cu(NO3)2?

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<h3>Answer:</h3>

3.3 × 10²³ molecules Cu(NO₃)₂

<h3>General Formulas and Concepts:</h3>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
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Left to Right<u> </u>

<u>Chemistry</u>

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<u>Stoichiometry</u>

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<u>Step 1: Define</u>

0.55 mol Cu(NO₃)₂

<u>Step 2: Identify Conversions</u>

Avogadro's Number

<u>Step 3: Convert</u>

[DA] Set up: $\displaystyle 0.55 \ mol \ Cu(NO_3)_2(\frac{6.022 \cdot 10^{23} \ molecules \ Cu(NO_3)_2}{1 \ mol \ Cu(NO_3)_2})$
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<em>Follow sig fig rules and round. We are given 2 sig figs.</em>

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3 years ago

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3 years ago

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When 125.0 g of ethylene (C2H4) burns in 60.0 grams of oxygen to give carbon dioxide and water, how many grams of CO2 are formed

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Answer:

66 g of CO₂

Solution:

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C₂H₂ + 5/2 O₂ → 2 CO₂ + H₂O

Or,

2 C₂H₂ + 5 O₂ → 4 CO₂ + 2 H₂O ------- (1)

Step 1: Find out the limiting reagent as;

According to Equation 1,

56.1 g (2 mole) C₂H₂ reacts with = 160 g (5 moles) of O₂

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It means for total combustion of Ethylene we require 356.5 g of O₂, but we are only provided with 60.0 g of O₂. Therefore, O₂ is the limiting reagent and will control the yield.

Step 2: Calculate Amount of CO₂ produced as;

According to Equation 1,

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