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Nina [5.8K]
3 years ago
14

Please help me with this question. Thank you.

Chemistry
2 answers:
DedPeter [7]3 years ago
6 0
36∨Kr^95 should be your answer.
krek1111 [17]3 years ago
3 0
In this nuclear reaction, a neutron is used to catalyze the decay of U-235. Four products were produced: Ba-139, two neutrons, and an unknown element X.

To calculate this, you must know that what you start with should be what you end with. The reaction occurred with 236 atomic mass units (U-235 and one neutron), so the final products should add up to 236.

Taking away Barium and the two neutrons:
236-141 = 95.
Now, we know that the element will have an overall mass of 95.

The number of protons should have stayed the same through the reaction as well, since the element didn’t undergo Beta or Positron decay. Starting with 92 protons (92 U), and subtracting the 56 contained in the Barium atom, the final number is 36 protons - the atomic number for Krypton.

Element X is Kr-95.
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2 years ago
When 1 mol of KBr(s) decomposes to its elements, 394 kJ of heat is absorbed. (a) Write a balanced thermochemical equation.
VladimirAG [237]

The balanced thermochemical equation is

KBr ------- K + 1/2 Br2

<h3>What is thermochemical equation? </h3>

A Thermochemical Equation is defined as the balanced stoichiometric chemical equation which includes the enthalpy change, ΔH.

The chemical equation for the decomposition of potassium bromide to its constituent elements bromine ans potassium :

KBr ----- K + Br2

The balanced thermochemical equation of the decomposition of potassium bromide to its constituent elements potassium and bromide as follows

KBr ------- K + 1/2 Br2

As the heat is absorbed in this reaction therefore, heat is positive.

Thus, we concluded that the balanced thermochemical equation is

KBr ------- K + 1/2 Br2

learn more about thermochemical equation:

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8 0
1 year ago
What is the charge of Fe(OH)3?
klasskru [66]
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6 0
3 years ago
If 56 grams of notrogen are used up by the reaction, how many grams of amonia will be produced? 1N2+3H2--&gt; 2NH3
djverab [1.8K]
1 mole of N2 produces 2 moles of NH3
OR...
14 x 2 grams of N2 produces 2(14 +3) grams of NH3
1 gram of N2 produces 34/28 grams of NH3
therefore, 56 grams produce (34/28 )x 56 =68 grams of NH3 

the answer thus would be 68 grams of NH3
5 0
3 years ago
Calculate the mass of water produced when 6.97 g of butane reacts with excess oxygen
andrew-mc [135]
The balanced reaction equation for the combustion of butane is as follows;
C₄H₁₀ + 13/2O₂ ---> 4CO₂ + 5H₂O 
the limiting reactant in this reaction is C₄H₁₀  This means that all the butane moles are consumed and amount of product formed depends on the amount of C₄H₁₀ used up.
stoichiometry of C₄H₁₀ to H₂O is 1:5
mass of butane used - 6.97 g
number of moles - 6.97 g / 58 g/mol = 0.12 mol
then the number of water moles produced - 0.12 mol x 5 = 0.6 mol
Therefore mass of water produced - 0.6 mol x 18 g/mol = 10.8 g
7 0
3 years ago
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