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asambeis [7]
4 years ago
6

What’s the molar mass of Mg(NO3)2

Chemistry
1 answer:
amid [387]4 years ago
8 0
Answer: 148.33 g/mol
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Answer the following questions in brief.<br>Why does silver get tarnished on exposure to air?​
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3 years ago
Calculate the temperature of a 0.50 mol sample of a gas at 0.987 atm and a volume of 12 L.
Aleonysh [2.5K]

Answer: 15.5^0C

Explanation:

According to ideal gas equation:

PV=nRT

P = pressure of gas = 0.987 atm

V = Volume of gas = 12 L

n = number of moles = 0.50

R = gas constant =0.0821Latm/Kmol

T =temperature =  ?

T=\frac{PV}{nR}

T=\frac{0.987atm\times 12L}{0.0820 L atm/K mol\times 0.50mol}=288.5K=(288.5-273)^0C=15.5^0C

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3 years ago
The reaction can be described using the equation: 2C2H25O24CO22H2O. How much C2H2is needed to react with 68.1 g of O2to produce
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Answer:

22.13g

Explanation:

We'll begin by writing a balanced equation for the reaction. This is illustrated below:

2C2H2 + 5O2 —> 4CO2 + 2H2O

Next, we'll calculate the mass of C2H2 and O2 that reacted from the balanced equation. This is illustrated below:

Molar Mass of C2H2 = (12x2) + (2x1)

= 24 + 2 = 26g/mol

Mass of C2H2 that reacted from the balanced equation = 2 x 26 = 52g

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Mass of O2 that reacted from the balanced equation = 5 x 32 = 160g

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From the balanced equation above,

52g of C2H2 reacted with 160g of O2.

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Xg of C2H2 = (52x68.1)/160

Xg of C2H2 = 22.13g

Therefore, 22.13g of C2H2 is needed to react with 68.1g of O2

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3 years ago
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