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KIM [24]
3 years ago
11

Which one of these aqueous solutions is a stronger electrolyte?

Chemistry
1 answer:
puteri [66]3 years ago
6 0
Answer : Option A) 0.5 M NaCl.

Explanation : A solution can be called as a stronger electrolyte which when dissolved in aqueous solution and produce ions in the solutions and is easily decomposed by electrolysis. Amongst the given options NaCl produces Na ions and Cl ions on dissolving with water rest all are not so readily soluble in water. As only salts which belong to<span> Group I elements are soluble electrolytes.</span>
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3 years ago
1. Ethylene glycol, commonly used in antifreezes, contains only carbon, hydrogen, and oxygen. When a sample of it is combusted i
11111nata11111 [884]

Answer:

Empirical formula = CH3O

Molecular formula = C2H6O2

Explanation:

Step 1: Data given

Mass of the sample = 23.46 grams

Mass of H2O = 20.42 grams

Molar mass of H2O = 18.02 g/mol

Mass of CO2 = 33.27 grams

Molar mass of CO2 = 44.01 G:mol

Atomic mass of C = 12.01 g/mol

Atomic mass of O = 16.0 g/mol

Atomic mass of H = 1.01 g/mol

Molar mass of the compound = 62.0 g/mol

Step 2: Calculate moles of H2O

Moles H2O = 20.42 grams / 18.02 g/mol

Moles H2O = 1.133 moles

Step 3: Calculate moles H

For 1 mol H2O we have 2 moles H  

For 1.133 moles H2O we have 2* 1.133 = 2.266 moles H

Step 4: Calculate mass H

Mass H = 2.266 moles * 1.01 g/mol

Mass H = 2.29 grams

Step 5: Calculate moles CO2

Moles CO2 = 33.27 grams / 44.01 g/mol

Moles CO2 = 0.7560 moles

Step 6: Calculate moles C

For 1 mol CO2 we have 1 mol C

For 0.7560 moles CO2 we have 0.7560 moles C

Step 7: Calculate mass C

Mass C = 0.7560 moles * 12.01 g/mol

Mass C = 9.08 grams

Step 8: Calculate mass O

Mass O = 23.46 grams - 9.08 grams - 2.29 grams

Mass O =12.09 grams

Step 9: Calculate moles O

Moles O = 12.09 grams / 16.0 g/moles

Moles O = 0.7556

Step 10: Calculate mol ratio

We divide by the smallest amount of moles  

C: 0.7560 moles / 0.7556 moles =1  

H: 2.266 moles / 0.7556 moles =3

O; 0.7556 / 0.7560 moles = 1

This means for 1 mol C we have 3 moles H and 1 mol O

The empirical formula is CH3O

Step 11: Calculate the molecular formula

The molar mass of the empirical formula is 31 g/mol

Step 11: Calculate molecular formula

We have to multiply the empirical formula by n

n = 62.0 g/mol / 31g/mol = 2

Molecular formula = 2*(CH3O)

Molecular formula = C2H6O2

5 0
3 years ago
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