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Ksivusya [100]
2 years ago
10

What is the volume of 1.60 grams of O2 gas at STP? (5 points)

Chemistry
2 answers:
tiny-mole [99]2 years ago
5 0

Answer:

  • <u><em>1.12 liters</em></u>

Explanation:

<u>Calculating number of moles</u>

  • Molar mass of O₂ = 32 g
  • n = Given weight / Molar mass
  • n = 1.6/32
  • n = 0.05 moles

<u>At STP</u>

  • One mole of O₂ occupies 22.4 L
  • Therefore, 0.05 moles will occupy :
  • 22.4 L x 0.05 = <u><em>1.12 L</em></u>
VladimirAG [237]2 years ago
4 0

1mol of any gas at STP contains 22.4L

moles of O_2

  • Given mass/molar mass
  • 1.6/32
  • 0.05mol

Now

Volume of O_2:-

  • 0.05(22.4)
  • 1.120L

Option D

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6.0 L of oxygen gas is at a temperature of 5K. If the temperature of the gas is lowered to 1K at constant pressure, what is the
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Answer:

THE NEW VOLUME AT 1 K IS 1.2 L

Explanation:

Using Charles' law which states that the volume of a given gas is directly proportional to its temperature provided the pressure remains constant.

Mathematically written as;

V1/T1 = V2/T2   at constant pressure

V1 = Initial volume = 6L

T1 = initial temperature = 5K

T2 = Final temperature = 1K

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Re-arranging the equation by making V2 the subject of the equation, we obtain;

V2 = V1 T2 / T1

V2 = 6 * 1 / 5

V2 = 1.2 L

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6 0
3 years ago
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A teacher wants to perform demonstration that illustrates both chemical and physical changes. Which would be the best demonstrat
saveliy_v [14]

Answer:

D) burning a candle

A demonstration that contains both physical and chemical changes will be BURNING OF A CANDLE.

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4 0
3 years ago
Please help with #2 and #3
Vaselesa [24]

Answer:

2. V_2=17L

3. V=82.9L

Explanation:

Hello there!

2. In this case, we can evidence the problem by which volume and temperature are involved, so the Charles' law is applied to:

\frac{V_2}{T_2}=\frac{V_1}{T_1}

Thus, considering the temperatures in kelvins and solving for the final volume, V2, we obtain:

V_2=\frac{V_1T_2}{T_1}

Therefore, we plug in the given data to obtain:

V_2=\frac{18.2L(22+273)K}{(45+273)K} \\\\V_2=17L

3. In this case, it is possible to realize that the 3.7 moles of neon gas are at 273 K and 1 atm according to the STP conditions; in such a way, considering the ideal gas law (PV=nRT), we can solve for the volume as shown below:

V=\frac{nRT}{P}

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V=\frac{3.7mol*0.08206\frac{atm*L}{mol*K}*273.15K}{1atm}\\\\V=82.9L

Best regards!

6 0
3 years ago
I find that there are 500 atoms of U-235 and 1500 atoms of Pb-207. If we assume the mineral contained only parent and no daughte
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Explanation:

From the question it can be infered that initially only parent atoms were present in the rock and  no daughter atom. So, initially there was only uranium atom and no lead atom. So, in total there were 500+1500= 2000 uranium atom. And no lead tom was there.

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