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Ksivusya [100]
2 years ago
10

What is the volume of 1.60 grams of O2 gas at STP? (5 points)

Chemistry
2 answers:
tiny-mole [99]2 years ago
5 0

Answer:

  • <u><em>1.12 liters</em></u>

Explanation:

<u>Calculating number of moles</u>

  • Molar mass of O₂ = 32 g
  • n = Given weight / Molar mass
  • n = 1.6/32
  • n = 0.05 moles

<u>At STP</u>

  • One mole of O₂ occupies 22.4 L
  • Therefore, 0.05 moles will occupy :
  • 22.4 L x 0.05 = <u><em>1.12 L</em></u>
VladimirAG [237]2 years ago
4 0

1mol of any gas at STP contains 22.4L

moles of O_2

  • Given mass/molar mass
  • 1.6/32
  • 0.05mol

Now

Volume of O_2:-

  • 0.05(22.4)
  • 1.120L

Option D

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Alex777 [14]

Option C. The object is returning to the start at a constant speed.

<h3>Data points of the Position vs Time graph</h3>

The following data points will be used to determine the motion of the object.

<u>Position               Time</u>

12                          4

10                          6

2                            8

0                           10

From the data above, the position of the object is decreasing towards zero or start point.

Thus, the object is returning to the start at a constant speed.

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8 0
2 years ago
An organic molecule is likely to contain all of these elements except: Answer C H O Ne N
eimsori [14]
Organic molecules typically do not contain the noble gases, so they would contain all but Ne
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3 years ago
Carbon-14 has a half-life of 5,730 years. How long will it take for 112. 5 g of a 120. 0-g sample to decay radioactively? 5,730
vichka [17]

The time taken by Carbon-14 to decay radioactively from 120g to 112.5g is 22,920 years.

<h3>How do we calculate the total time of decay?</h3>

Time required for the whole radioactive decay of any substance will be calculated by using the below link:

T = (n)(t), where

  • t = half life time = 5730 years
  • n = number of half life required for the decay

Initial mass of Carbon-14 = 120g

Final mass of Carbon-14 = 112.5g

Left mass = 120 - 112 = 7.5g

Number of required half life for this will be:

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  • 2: 60 → 30
  • 3: 30 → 15
  • 4: 15 → 7.5

4 half lives are required, now on putting values we get

T = (4)(5730) = 22,920 years

Hence required time for the decay is 22,920 years.

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3 0
2 years ago
How does a sciences form a hypothesis
Oduvanchick [21]

they try to ask themselves why certain things happen and they try to make an educated guess of what will happen.

7 0
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Alina [70]

Answer:

last choice

Explanation:

oxidation and reduction can be defined in terms of adding or removing oxygen to a compound

oxidation is gaining oxygen

reduction is to loss oxygen

5 0
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