Find zeroes and multiplicity for y=(2x +3)(x -1)^2
1 answer:
Answer:
zeros : -3/2 , multiplicity = 1
1 , multiplicity = 2
Step-by-step explanation:
To find zeros we set each factor =0 and solve for x
2x+3 =0
subtract 3 on both sides
2x= -3
divide by 2 on both sides
x= -3/2
The exponent of (2x+3) is 1 so multiplicity =1
Now we set (x-1)^2 =0
take square root on both sides
x-1 =0
add 1 on both sides
x=1
For (x-1)^2 the exponent is 2
So multiplicity = 2
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Answer:
Applying Quotient and power rule. Graphically, for x>0 both curves coincide.
Step-by-step explanation:
1) Firstly, by applying the Quotient and then the Power Rule, we have a subtraction of the argument and, finally the exponent turns to be the coefficient. As it follows:
2) Check the graph below to see this equivalence. to see x>0 they both coincide.
First, simplify the negative addition.
Follow the order of operations by dividing first.
Add and subtract from left to right.