Find zeroes and multiplicity for y=(2x +3)(x -1)^2
1 answer:
Answer:
zeros : -3/2 , multiplicity = 1
1 , multiplicity = 2
Step-by-step explanation:
To find zeros we set each factor =0 and solve for x
2x+3 =0
subtract 3 on both sides
2x= -3
divide by 2 on both sides
x= -3/2
The exponent of (2x+3) is 1 so multiplicity =1
Now we set (x-1)^2 =0
take square root on both sides
x-1 =0
add 1 on both sides
x=1
For (x-1)^2 the exponent is 2
So multiplicity = 2
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Answer:
p(t) = 0 for t = 1
p(t) = 1 for t = 1/8 = 8^-1
Step-by-step explanation:
the graph you will have to do yourself.
just go there and type in
well, don't type "log" in letters.
you start by typing the "-" sign, and then you need to look up the functions by clicking on the "funcs" button and look for the log functions .
pick the
option. and then simply enter 8 as the first parameter in the {} brackets and x as the second in the () brackets.
and then you see.
any logarithm is 0 for x (or t) = 1.
because any a⁰ = 1.
and the logarithm gives you that exponent of the base number that leads to the given x value.
in other words : a logarithm is the inverse function of an exponential function.
the exponential function is
y = a^x
and the logarithm then determines
that is all.
and
means that the logarithm itself delivered -1.
and 8^-1 = 1/8
so, p(t) = 1 for t = 1/8
I’m not sure if your answer is right but here’s how to solve it
