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AlexFokin [52]
3 years ago
9

Evaluate y = ln (x − 2) for the following values of x. Round to the nearest thousandth.

Mathematics
2 answers:
jek_recluse [69]3 years ago
8 1

Answer:

1)0

2)0.693

3)1.386

The first graph

Step-by-step explanation:

MatroZZZ [7]3 years ago
5 1

Answer:

0

0.693

1.386

graph A

Step-by-step explanation:

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Hello and Good Morning/Afternoon

<u>Let's take this problem step-by-step</u>:

<u>To find the solution to a system of equation</u>

  ⇒ <em>must set</em> the equations equal to each other

     ⇒ and solve

<u>Let's put that into action</u>

  x^2-2x+3 = -2x + 12\\x^2-2x+2x+3-12=0\\x^2-9=0\\(x+3)(x-3)=0

  • At this point, to make the whole thing equal zero

          ⇒ either 'x+3' or 'x-3' equals zero

              ⇒ must find 'x' that satisify either equation

                    x-3=0\\x=3\\\\x+3=0\\x=-3

<u>Let's find the corresponding f(x) to each x-value</u>

  f(3) = -2(3)+12=-6+12 = 6\\\\f(-3) = -2(-3) + 12=6+12=18

<u>Therefore the solutions are (3,6) and (-3,18)</u>

<u />

<u>Answer: (3,6), (-3,18)</u>

<u></u>

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Step-by-step explanation:

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Read 2 more answers
A bullet is fired straight up from a gun with initial velocity 1120 feet per second at an initial height of 8 feet. Use the form
Dafna1 [17]

Answer:

70 seconds

Step-by-step explanation:

Given that;

The initial velocity v_o of the bullet fired = 1120 ft/s

Initial height h = 8 feet

The expression to determine how many seconds it takes the bullet to hit the ground is:

h = -16t^2 +v_ot + 8

Thus;

Replacing the value of v_o =  1120 and h = 0 (i.e. when h =0) in the above expression; we have:

0= -16t^2 +(1120)t + 8

=  -16t^2 +(1120)t + (8-0)

= -16t² + 1120t + 8

mulitiply through by (-)

= 16t² -1120t - 8

Divide through by 8

= 2t² -  140t - 1

The above expression forms a quadratic equation.

where;

a = 2

b = -140

c = - 1

So, by using the quadratic formula \dfrac{-b \pm \sqrt{b^2-4ac}}{2a}, we have:

= \dfrac{-(-140) \pm \sqrt{(-140)^2-4(2)(-1)}}{2(2)}

= \dfrac{140 \pm \sqrt{19600-(-8)}}{4}

= \dfrac{140 \pm \sqrt{19608}}{4}

= \dfrac{140 \pm 140}{4}

=\dfrac{140+ 140}{4} \ \ \ OR \ \ \  \dfrac{140-140}{4}

=\dfrac{280}{4} \ \ \ OR \ \ \  0

= 70

Thus, the time (in seconds) it took the bullet to it the ground = 70 seconds

6 0
3 years ago
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