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Gennadij [26K]
4 years ago
14

How many moles of CaCl2 are required to prepare 2.00 liters of 0.700 M CaCl2?

Chemistry
1 answer:
suter [353]4 years ago
5 0
The dissolution<span> of </span>calcium chloride<span> in </span>water<span>. </span>CaCl2(s<span>)--> </span>Ca^2+ (aq) +2 Cl^-1<span> (</span>aq<span>). A) </span>Use<span> the </span>data<span> from</span>appendix C<span>. and </span>below<span> to </span>determine Delta H<span> of </span>formation<span> in </span>kj/mol<span> for this </span>process<span> (</span>deltaH(Ca^2+(aq)=-542.8 kj/mol<span>).</span>
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What is the pH of the solution if the [H+] is 1 x 10-12 ?
jarptica [38.1K]

Answer:

<h2>12</h2>

Explanation:

The pH of a solution can be found by using the formula

pH = - log [ {H}^{+} ]

From the question we have

pH =  -  log(1 \times  {10}^{ - 12} )  \\

We have the final answer as

<h3>12</h3>

Hope this helps you

5 0
3 years ago
Can you live without chemical reactions
Oliga [24]

Answer:

no

Explanation:

your body wouldnt be able to repair, move, or do anything for that matter if we didnt consistently have chemical reactions in us.

7 1
3 years ago
Read 2 more answers
What is the difference between a conductor and an insulator?
USPshnik [31]

Answer:materials that impede the free flow of electrons from atom to atom and molecule to molecule.

6 0
2 years ago
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A hydrogen atom requires a minimum energy of 2.18×10^-18 J atom to remove an electron from its ground state level. Determine whe
frosja888 [35]
Just find the energy of the <span>blueviolet light with a wavelength of 434.0 nm using the formula:

E  = hc / lambda

E = energy
c= speed of light =  3 x 10^8 m/s
h = planck's constant =  6.6 x 10^{-34}  m^2 kg / s
lambda =  434 nm =  434 x 10^{-9} m

Putting these values (with appropriate units) in the above formula :

we get:  Energy, E = 4.5 x 10^{-19} J

E = 0.45 x 10^{-18} J

Now, the </span>minimum energy is 2.18×10^-{18} J but our energy is 0.45 x 10^{-18} J which is less.
<span>Means the electron will not be removed

</span>
5 0
3 years ago
Copper has a specific heat of 0.385 J/gºC.
Anna71 [15]

Answer:

The final temperature is 348.024°C.

Explanation:

Given data:

Specific heat of copper = 0.385 j/g.°C

Energy absorbed = 7.67 Kj (7.67×1000 = 7670 j)

Mass of copper = 62.0 g

Initial temperature T1 = 26.7°C

Final temperature T2 = ?

Solution:

Specific heat capacity:

It is the amount of heat required to raise the temperature of one gram of substance by one degree.

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

ΔT = T2 - T1

Q = m.c. ΔT

7670 J = 62.0 g × 0.385  j/g °C ×( T2- 26.7 °C )

7670 J = 23.87 j.°C ×( T2- 26.7 °C )

7670 J / 23.87 j/°C = T2- 26.7 °C

T2- 26.7 °C = 321.324°C

T2 = 321.324°C + 26.7 °C

T2 = 348.024°C

The final temperature is 348.024°C.

6 0
4 years ago
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