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3 years ago

How many moles of CaCl2 are required to prepare 2.00 liters of 0.700 M CaCl2?

1 answer:

5 0

The dissolution of calcium chloride in water. CaCl2(s)--> Ca^2+ (aq) +2 Cl^-1 (aq). A) Use the data fromappendix C. and below to determine Delta H of formation in kj/mol for this process (deltaH(Ca^2+(aq)=-542.8 kj/mol).

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I REALLY NEED HELP can someone help me please I’ll make you brainliest ! :)

Nikitich [7]

Answer:

Explanation:

All thing in option c is flammable

5 0

2 years ago

Read 2 more answers

if a sample of gas at 25.2 c has a volume of 536mL at 637 torr, what will its volume be if the pressure is increased to 712 torr

nignag [31]

Considering ideal gas:
PV= RTn

T= 25.2°C = 298.2 K

P1= 637 torr = 0.8382 atm

V1= 536 mL = 0.536 L

:. R=0.082 atm.L/K.mol

:. n= (P1V1)/(RT) = ((0.8382 atm) x (0.536 L))/
((0.082 atmL/Kmol) x (298.2K))

:. n= O.0184 mol

Then,
P2= 712 torr = 0.936842 atm

V2 = RTn/P2 = [(0.082atmL/
Kmol) x (298.2K) x (0.0184mol) ]/(0.936842atm)

:.V2 = 0.4796 L
OR
V2 = 479.6 ml

6 0

3 years ago

A substance is highly malleable and has a shiny luster. Which of the following best explains the probable position of the substa

Aleks04 [339]

The answer is D only metals are shiny and highly malleable

5 0

2 years ago

Read 2 more answers

Write the ground-state electron configuration for the chloride ion.You may write either the full or condensed electron configura

dalvyx [7]

Answer:

$1s^22s^22p^63s^23p^6$

Explanation:

Chlorine is the element of group 17 and third period. The atomic number of chlorine is 17 and the symbol of the element is Cl.

The electronic configuration of the element chlorine is:-

$1s^22s^22p^63s^23p^5$

Chloride ion is formed when chlorine atom gain one more electron. So, the ground-state electron configuration for the chloride ion is:-

$1s^22s^22p^63s^23p^6$

8 0

3 years ago

The source of bitterness in dark chocolate is the compound theobromine, an alkaloid present in cocoa beans. In a sample of dark

spin [16.1K]

Answer: 193 mg of theobromine are present in the sample.

Explanation:

According to avogadro's law, 1 mole of every substance occupies 22.4 L at STP and contains avogadro's number of particles.

To calculate the moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given molecules}}{\text {Avogadros number}}=\frac{6.45\times 10^{20}}{6.023\times 10^{23}}=1.07\times 10^{-3}moles$

1 mole of theobromine $(C_7H_8N_4O_2)$ weigh = 180 g

$1.07\times 10^{-3}moles$ of theobromine $(C_7H_8N_4O_2)$ weigh = $\frac{180}{1}\times 1.07\times 10^{-3}=0.193g=193mg$ (1g=1000mg)

193 mg of theobromine are present in the sample.

5 0

3 years ago