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vagabundo [1.1K]
3 years ago
8

What is the maximum number of electrons in the following energy leve? n-3232818​

Chemistry
1 answer:
atroni [7]3 years ago
8 0
The answer is 32!!!!!!!!!!
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Consider a block G with mass of 49.231 g and a volume of 23.8 ml what is its density
Advocard [28]

Answer:

ρ = 2.07 g/mL

Explanation:

Step 1: Given data

  • Mass of the block G (m): 49.231 g
  • Volume of the block G (V): 23.8 mL

Step 2: Calculate the density (ρ) of the block G

The density is an intrinsic property, equal to the mass of the block divided by its volume.

ρ = m/V

ρ = 49.231 g/23.8 mL

ρ = 2.07 g/mL

The density of the block G is 2.07 g/mL.

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Diane is able to dissolve 25g of coffee whitener in 250mL of 30°C water before it reaches saturation point. What is the solubili
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i think it is 13

Explanation:

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What happens to electrons in the photoelectric effect?
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The correct answer is B. on Apex!

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Which of the following may indicate that a chemical reaction has occurred?
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D, all of the above

Explanation:

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2 years ago
Partner Namets) For each of the following reactions carried out: Write the balanced chemical equation, the full ionic equation,
torisob [31]

Answer : The full balanced ionic equation will be,

2KI(aq)+Pb(NO_3)_2(aq)\rightarrow 2KNO_3(aq)+PbI_2(s)

Reactants are lead nitrate and potassium iodide.

Products are lead iodide and potassium nitrate.

The spectator ions are, K^+,NO_3^-

Explanation :

Complete ionic equation : In complete ionic equation, all the substance that are strong electrolyte and present in an aqueous are represented in the form of ions.

Net ionic equation : In the net ionic equations, we are not include the spectator ions in the equations.

Spectator ions : The ions present on reactant and product side which do not participate in a reactions. The same ions present on both the sides.

When potassium iodide react with lead nitrate then it gives potassium nitrate and lead iodide as a product.

The full balanced ionic equation will be,

2KI(aq)+Pb(NO_3)_2(aq)\rightarrow 2KNO_3(aq)+PbI_2(s)

The ionic equation in separated aqueous solution will be,

2K^+(aq)+2I^{-}(aq)+Pb^{2+}(aq)+2NO_3^{-}(aq)\rightarrow PbI_2(s)+2K^+(aq)+2NO_3^{-}(aq)

In this equation, K^+\text{ and }NO_3^- are the spectator ions.

By removing the spectator ions from the balanced ionic equation, we get the net ionic equation.

The net ionic equation will be,

Pb^{2+}(aq)+2I^{-}(aq)\rightarrow PbI_2(s)

4 0
3 years ago
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