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jok3333 [9.3K]
3 years ago
14

How do you use the periodic table to determine the mass of 4 moles of oxygen? Explain your process for getting the answer. Use s

entences or steps.
Chemistry
2 answers:
Nitella [24]3 years ago
8 0

Answer:

read back through your lesson and get the formula

Explanation:

crimeas [40]3 years ago
8 0

Answer:

mass O2 = moles(O2) × molar mass(O2) (a) Calculate moles(Mg) = mass(Mg) ÷ molar mass(Mg) moles(Mg) = 12.2 ÷ 24.31 = 0.50 mol. ...

mass MgO = moles(MgO) × molar mass(MgO) (a) Calculate moles Mg. moles(Mg) = mass(Mg) ÷ molar mass(Mg)

Explanation:

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Which of the following do you expect to have soil with the highest fertility
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It would help if I could see the specific answer choices, but an environment that would have lots of oxygen, water, decaying organisms and sunlight would be the answer (ex. the forest or riverbed)
7 0
3 years ago
The specific heat of a certain type of cooking oil is 1.75 J/(g⋅°C). How much heat energy is needed to raise the temperature of
Mademuasel [1]

Answer:

\large \boxed{\textbf{609 kJ}}  

Explanation:

The formula for the heat absorbed is

q = mCΔT

Data:

m = 2.07 kg

T₁ = 23 °C

T₂ = 191 °C

C = 1.75 J·°C⁻¹g⁻¹

Calculations:

1. Convert kilograms to grams

2.07 kg = 2070 g

2. Calculate ΔT

ΔT = T₂ - T₁ = 191 - 23  = 168 °C

3. Calculate q

q = \text{2070 g} \times 1.75 \text{ J$^{\circ}$C$^{-1}$g$^{-1}$} \times 168 \,^{\circ}\text{C} = \text{609 000 J} = \textbf{609 kJ}\\\text{The heat energy required is }\large \boxed{\textbf{609 kJ}}

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3 years ago
On the basis of dipole moments and/or hydrogen bonding, explain in a qualitative way the differences in the boiling points of ac
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7 0
3 years ago
Give an example of how natural selection could benefit a species. Justify your response in two or more complete sentences.
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4 0
3 years ago
If the solubility of KCl in 100 mL of H₂O is 34 g at 20 °C and 43 g at 50 °C, label each of the following solutions as unsaturat
sertanlavr [38]

Answer:

a) Unsaturated

b) Supersaturated

c) Unsaturated

Explanation:

A saturated  solution contains the <u>maximum amount of a solute that will dissolve in a given  solvent at a specific temperature</u>.

An unsaturated solution contains <u>less solute than it  has the capacity to dissolve. </u>

A supersaturated solution, <u>contains more  solute than is present in a saturated solution</u>. Supersaturated solutions are not very  stable. In time, some of the solute will come out of a supersaturated solution as crystals.

According to these definitions and considering that the solubility of KCl in 100 mL of H₂O at <u>20 °C is 34 g</u>, and at <u>50 °C is 43 g</u> we can label the solutions:

a) 30 g in 100 mL of H₂O at 20 °C  ⇒ unsaturated

b) 65 g in 100 mL of H₂O at 50 °C  ⇒ supersaturated

c) 42 g in 100 mL of H₂O at 50 °C and slowly cooling to 20 °C to give a clear solution <u>with no precipitate</u> ⇒ unsaturated (if it were saturated it would have had precipitate)

8 0
3 years ago
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