Where is the majority of the mass located in an atom

There is an electric field in the region between the two plates. The magnitude of this electric field is ed. This imposes anothe

krok68 [10]

Answer:

it is essential that the charge on the plates are of the same magnitude, but in the opposite direction

Explanation:

The configuration of parallel plates is called a capacitor and is widely used to create constant electric fields inside.

To obtain this field it is essential that the charge on the plates are of the same magnitude, but in the opposite direction

This is so that the fields created by each plate can be added inside and subtracted from the outside of the plates

5 0

3 years ago

Wich of yhe following is true A mass drpendent on gravity and weight is dependent on gravity B mass is not dependent on gravity

Diano4ka-milaya [45]

C I believe is the answer

6 0

3 years ago

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If a poison is ingested that prevents the release of acetylcholine, which one of the following would occur at a myoneural juncti

kirill115 [55]

Had to look for the options and here is my answer.
Given the situation that a poison is consumed and this prevented the acetylcholine release, the one that would most likely occur at a myoneural junction is that "sodium and potassium gates on the motor end plate will not open". Hope this helps.

4 0

3 years ago

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A car of mass 800 kg is moving at a uniform velocity of 72 km/hr. Find its

77julia77 [94]

Answer:

hope its helpful to uh...

6 0

3 years ago

A very long, straight wire carries a current of 19.0 A in the +k direction. An electron 1.9 cm from the center of the wire in th

Anestetic [448]

(a) $1.03\cdot 10^{-16} N$ , -k direction

First of all, let's find the magnetic field produced by the wire at the location of the electron:

$B=\frac{\mu_0 I}{2 \pi r}$

where

I = 19.0 A is the current in the wire

r = 1.9 cm = 0.019 m is the distance of the electron from the wire

Substituting,

$B=\frac{(1.256\cdot 10^{-6})(19.0A)}{2 \pi (0.019 m)}=2\cdot 10^{-4} T$

and the direction is +j direction (tangent to a circle around the wire)

Now we can find the force on the electron by using:

$F=qvBsin \theta$

where

$q=1.6\cdot 10^{-19}C$ is the electron's charge

$v=3.23\cdot 10^6 m/s$ is the electron speed

$B=2\cdot 10^{-4} T$ is the magnetic field

$\theta$ is the angle between the direction of v and B

In this case, the electron is travelling away from the wire, while the magnetic field lines (B) form circular paths around the wire: this means that v and B are perpendicular, so $\theta=90^{\circ}, sin \theta=1$ . So, the force on the electron is

$F=(1.6\cdot 10^{-19}C)(3.23\cdot 10^6 m/s)(2\cdot 10^{-4} T)(1)=1.03\cdot 10^{-16} N$

The direction is given by the right hand rule:

- Index finger: direction of motion of the electron, +i direction (away from the wire)

- Middle finger: direction of magnetic field, +j direction (tangent to a circle around the wire)

- Thumb: direction of the force --> since the charge is negative, the sign must be reversed, so it means -k direction (anti-parallel to the current in the wire)

(b) $1.03\cdot 10^{-16} N$ , +i direction

The calculation of the magnetic field and of the force on the electron are exactly identical as before. The only thing that changes this time is the direction of the force. In fact we have:

- Index finger: direction of motion of the electron, +k direction (parallel to the current in the wire)

- Middle finger: direction of magnetic field, +j direction (tangent to a circle around the wire)

- Thumb: direction of the force --> since the charge is negative, the sign must be reversed, so it means +i direction (away from the wire)

(c) 0

In this case, the electron is moving tangent to a circle around the wire, in the +j direction. But this is exactly the same direction of the magnetic field: this means that v and B are parallel, so $\theta=0, sin \theta=0$ , therefore the force on the electron is zero.

6 0

3 years ago