Answer: force of gravity on the body due to height difference above the earth's surface
Explanation: as you increase the height of a body above ground, you do work against gravity in moving it from a point on the earth's surface to that point. So a body falling has a stored up gravito-potential energy which acts on it downward due to its mass, accelerating it downwards
Answer b): kinetic energy of the body
Explanation: the downward force produces an acceleration of magnitude 9.81m/s2 downwards which means an increasing velocity. This increasing velocity means the kinetic energy of the body is increasing (kinetic energy is proportional to velocity of the body squared)
Answer:
Vf₂ = 2 Vf₁
It shows that final speed of Joe is twice the final speed of Jim.
Explanation:
First, we analyze the final speed of Jim by using first equation of motion:
Vf₁ = Vi + at
where,
Vf₁ = final speed of Jim
Vi = initial speed of Jim = 0 m/s
a = acceleration of Jim
t = time of acceleration for Jim
Therefore,
Vf₁ = at ---------------- equation (1)
Now, we see the final speed of Joe. For Joe the parameters will become:
Vf = Vf₂
Vi = 0 m/s
a = a
t = 2t
Therefore,
Vf₂ = 2at
using equation (1):
<u>Vf₂ = 2 Vf₁</u>
<u>It shows that final speed of Joe is twice the final speed of Jim.</u>
Answer:
d jjh hhv g 7655 ijv 77_* uyfgj 3&88 huih
The tangential speed of an orbiting object is 
Explanation:
The tangential speed of an orbiting object is defined as the ratio between the distance covered in one revolution and the period of revolution:
where
d is the distance covered during one period
T is the orbital period
However, the distance covered during one period is the circumference of the circle:
where
r is the radius of the circle
Substituting the 2nd equation into the 1st equation, we find:
So, this is the final expression for the tangential speed of an orbiting object.
Learn more about circular motion:
brainly.com/question/2562955
brainly.com/question/6372960
#LearnwithBrainly
Answer:
The magnitude of the induced emf is
Ф = 5.419 x 10⁻³ V
Explanation:
Given:
r = 23.0 cm = 0.23 m
β₁ = 0.50 T
β₂ = 2.50 * 0.50 T = 1.25 T
Calculate the magnitude of the induced emf the magnetic field is increasing
Ф = A * Δβ / Δt
A = π * r² = π * 0.23² m = 0.166 m²
Ф = 0.166m² * (1.25 - 0.5) T / 23 s
Ф = 5.419 x 10⁻³ V
