Answer: a) 16Hz, 3m b) 48Hz, 1mc) 80Hz, 0.6m
Explanation:
a) Fundamental frequency in string is represented as Fo = V/2L where;
Fo is the fundamental frequency
V is the speed of the transverse wave = 48m/s
L is the length of the wire. = 1.50m
Substituting this values in the formula given we have;
Fo = 48/2(1.5)
Fo = 48/3
Fo = 16Hz
The fundamental tone is therefore 16Hz
Using v =f¶
Where f is the frequency and ¶ is the wavelength, the wavelength of the fundamental note will be;
¶ = v/fo
¶ = 48/16 = 3m
b) Overtones or harmonics is the multiple integral of the fundamental frequency. The multiples are I'm arithmetical progression.
First overtone f1 = 2fo
Second overtone f2 = 3fo etc.
Since fo = 16Hz
Second overtone f2 = 3×16 = 48Hz
¶ = v/f2 = 48/48
¶ = 1m
c) Fourth harmonic or overtone will be f4 = 5fo
F4 = 5×16 = 80Hz
The fourth harmonic is therefore 80Hz
¶ = v/f4 = 48/80
¶ = 0.6m
1. 168.1 Hz
To find the apparent frequency heard by the driver in the car, we can use the formula for the Doppler effect:

where
f is the original sound of the horn
v is the speed of sound
is the velocity of the observer (the driver and the car), which is positive if the observer is moving towards the source and negative if it is moving away
is the velocity of the sound source (the train), which is positive if the source is moving away from the observer and negative otherwise
In this problem we have, according to the sign convention used:

Substituting, we find:

2. 
The speed of light can be calculated as

where
d is the distance travelled
t is the time taken
In this problem:
is the total distance travelled by the laser beam (twice the distance between the Earth and the Moon)
t = 2.60 s is the time taken
Substituting in the formula,

Oxygen enters the blood Through your lungs
Which excerpt are you talking about?
Answer:
Explanation:
An inelastic collision is one where 2 masses collide and stick together, moving as a single mass after the collision occurs. When we talk about this type of momentum conservation, the momentum is conserved always, but the kinetic momentum is not (the velocity changes when they collide). Because there is direction involved here, we use vector addition. The picture before the collision has the truck at a mass of 3520 kg moving north at a velocity of 18.5. The truck's momentum, then, is 3520(18.5) = 65100 kgm/s; coming at this truck is a car of mass 1480 kg traveling east at an unknown velocity. The car's momentum, then, is 1480v. The resulting vector (found when you pick up the car vector and stick the initial end of it to the terminal end of the truck's momentum vector) forms the hypotenuse of a right triangle where one leg is 65100 kgm/s, and the other leg is 1480v. Since we already know the final velocity of the 2 masses after the collision, we can use that to find the final momentum, which will serve as the resultant momentum vector in our equation (we'll get there in a sec). The final momentum of this collision is
p = mv and
p = (3520 + 1480)(13.6) so
p = 68000. Final momentum. The equation for this is a take-off of Pythagorean's Theorem and the one used to find the final magnitude of a resultant vector when you first began your vector math in physics. The equation is
which, in words, is
the final momentum after the collision is equal to the square root of the truck's momentum squared plus the car's momentum squared. Filling in:
and
and
and
and
so
v = 13.3 m/s at 72.6°