By SAS property, ABC ≅ DCB.
<h3>How to prove the deductions</h3>
In this question we have to proof ABCD has congruent diagonal. By SAS property and reflexive property it can be proved as follows:
Given:
ABCD is a rectangle.
Prove:
Diagonal AC ≅ Diagonal BD
From the question,
As we can see that, ABCD is a rectangle, it is also a parallelogram.
Thus, ABCD is a parallelogram, opposite sides of a parallelogram are congruent.
⇒ AB ≅ DC
⇒ BC ≅ BC (Reflexive Property of Congruence)
Hence, ∠ABC and ∠DCB are right angles by the definition of rectangle.
∠ABC ≅ ∠DCB (all right angles are congruent)
Therefore, by SAS property, ABC ≅ DCB.
⇒ segment AC ≅ segment BD
Learn more about rectangular congruency here:
brainly.com/question/7162498
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The answer is A
hope this helps
Answer:
No
Step-by-step explanation:
Since the total amount of students in the graph is 50, this means that 1 in every 25 students choose sports. There are however 200 students and not 50 in the question. 25 goes into 200 8 times, so there are 8 students doing sports.
1. 2(4) - 4y = 20
8 -4y = 20
8-8 -4y = 20 - 8
-4/-4y = 12/-4
y = -3
