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serg [7]
3 years ago
8

Which numbers are a distance of 3.2 units from −4 on a number line? A number line with increments of .5 with a range of 0 to neg

ative 7.5 Select each correct answer. −7.4 −7.2 −6.3 −4.2 −3.8 −0.8
Mathematics
1 answer:
yulyashka [42]3 years ago
7 0

Answer: The numbers on a distance of 3.2 units from −4 on a number line are -7.2 and - 0.8 .

Step-by-step explanation:

The numbers on a number line are from - infinity to + infinity whose center is at 0.Om left sides of 0 , there are negative integers and on the right side there are positive integers.

So, The numbers on a distance of 3.2 units from −4 on a number line are

-4 - 3.2 and -4+3.2

= - (4+3.2)  and - (4-3.2)

= -7.2 and - 0.8

Hence, the numbers on a distance of 3.2 units from −4 on a number line are -7.2 and - 0.8 .

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Find the area of the figure
VLD [36.1K]

Answer:

132 cm²

Step-by-step explanation:

Consider the shape as a trapezoid with a rectangle added on top.

The area of the trapezoid is (7+19)/2 × 8 =104

The area of the rectangle is 7×4 = 28

Add the two areas: 104+28= 132

OR consider the shape as a tall rectangle with the two triangles added to the sides.

The area of the rectangle is 7(4+8) = 84

The area of the triangles is 8(19-7)/2= 48

[Each triangle is 24 cm²]

Add those areas

84+48=132

Same result: 132 cm²

4 0
3 years ago
Which is the minimum or maximum value of the given function? a. The function has a minimum value of -2 b. The function has a min
Alex17521 [72]

Answer:

The function f(x) is not given, I used a different function but the approach and steps is the same .

Step-by-step explanation:

  • Given the function f(x) = 2x2 - 8x + 5

compare with the normal quadratic equation ; ax2 + bx + c = f(x)

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As such, it has a minimum

hence for minimum value; x = -b/2a

x = -(-8)/2 x 2

x = 8/4 = 2

plugging the values of x in f(x) ; f(2) = 2(2)^2 -8(2) + 5

f(2) = -3, hence it has minimum value and the minimum value is -3

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Can u explain it a little more clearly...
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Answer:

The answer will be 85,968

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