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serg [7]
3 years ago
8

Which numbers are a distance of 3.2 units from −4 on a number line? A number line with increments of .5 with a range of 0 to neg

ative 7.5 Select each correct answer. −7.4 −7.2 −6.3 −4.2 −3.8 −0.8
Mathematics
1 answer:
yulyashka [42]3 years ago
7 0

Answer: The numbers on a distance of 3.2 units from −4 on a number line are -7.2 and - 0.8 .

Step-by-step explanation:

The numbers on a number line are from - infinity to + infinity whose center is at 0.Om left sides of 0 , there are negative integers and on the right side there are positive integers.

So, The numbers on a distance of 3.2 units from −4 on a number line are

-4 - 3.2 and -4+3.2

= - (4+3.2)  and - (4-3.2)

= -7.2 and - 0.8

Hence, the numbers on a distance of 3.2 units from −4 on a number line are -7.2 and - 0.8 .

You might be interested in
8/x-5 - 9/x-4 = 5/x^2-9x+20
adelina 88 [10]
If you're using the app, try seeing this answer through your browser:  brainly.com/question/2752942

_______________


Solve the equation:

\mathsf{\dfrac{8}{x-5}-\dfrac{9}{x-4}=\dfrac{5}{x^2-9x+20}\qquad\qquad(x\ne 5~and~x\ne 4)}


Reduce the fractions at the left side so that they have the same denominator:

\mathsf{\dfrac{8(x-4)}{(x-5)(x-4)}-\dfrac{9(x-5)}{(x-4)(x-5)}=\dfrac{5}{x^2-9x+20}}\\\\\\
\mathsf{\dfrac{8x-32}{x^2-4x-5x+20}-\dfrac{9x-45}{x^2-4x-5x+20}=\dfrac{5}{x^2-9x+20}}\\\\\\
\mathsf{\dfrac{8x-32}{x^2-9x+20}-\dfrac{9x-45}{x^2-9x+20}=\dfrac{5}{x^2-9x+20}}\\\\\\
\mathsf{\dfrac{8x-32-(9x-45)}{x^2-9x+20}=\dfrac{5}{x^2-9x+20}}


Numerators must be equal:

\mathsf{8x-32-(9x-45)=5}\\\\
\mathsf{8x-32-9x+45=5}\\\\
\mathsf{8x-9x=5+32-45}\\\\
\mathsf{-x=-8}\\\\
\mathsf{x=8}\quad\longleftarrow\quad\textsf{this is the solution.}


I hope this helps. =)


Tags:  <em>rational equation fraction solution algebra</em>

7 0
3 years ago
Which description best describes the solution to the following system of equations?
matrenka [14]

Answer:the base root becomes 45

Step-by-step explanation:

8 0
2 years ago
Read 2 more answers
How do you write this in standard notation<br><br>6x10 to the power of 3
Olin [163]
The way to write this would be 6000
7 0
3 years ago
Rewrite using a single positive exponent.<br> 6^5<br> 6
Fiesta28 [93]

Answer:

6^{4}

Step-by-step explanation:

using the rule of exponents

\frac{a^{m} }{a^{n} } = a^{(m-n)}

note that 6 = 6^{1} , then

\frac{6^{5} }{6} = 6^{(5-1)} = 6^{4}

7 0
2 years ago
I WILL GIVE YOU BRAINLYEST!! PLSS HELP ME ASAP!!
kaheart [24]
Omg i can help you because I was having trouble with the same thing! so the Total Surface Area= Ph+2B meaning you have to find the P=perimeter Lx2+Wx2, then the height, then base. the lateral area is Ph+B :)!!
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