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Law Incorporation [45]
2 years ago
14

Which function represents g(x), a reflection of f(x) = 4across the x-axis?

Mathematics
2 answers:
Anna71 [15]2 years ago
7 0

Answer:

g(x)=-4(2)^{-x}

Step-by-step explanation:

Given: The graph of f(x) (blue color)

f(x) reflection across x-axis to get g(x).

Using to find the equation of f(x)

The graph looks like a exponential decay whose y-intercept (0,4) and passing point (1,2).

f(x)=4(2)^{-x}

Reflection across x-axis

y\rightarrow -y

g(x)=-f(x)

The function g(x) represents by

g(x)=-4(2)^{-x}

Hence, The g(x)=-4(2)^{-x} is reflection of f(x) across x-axis.

fiasKO [112]2 years ago
3 0

Answer:

Option C g(x) = -4

Step-by-step explanation:

In the question a function f(x) =4 is given and we are required to tell the reflection g(x) of the given function.

The rule of reflection for a function says that:

f(x) -> - f(x)

So, in our case the value of function is f(x) = 4, after reflection the value across the x-axis the value will become negative i.e -4,

so the required function g(x) = - 4

Hence Option C g(x) = -4 is correct option.

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200 baseball cards

Step-by-step explanation:

We write the expression:

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What are the first two steps to solve this equation 4(2x - 3) = 1
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Answer:

x=13/8

Step-by-step explanation:

8x-12=1

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What are the interest costs and other fees for using a credit card called?
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C: Finance Charge

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What fractions are equivalent to 40
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If that helps?

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3 years ago
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Suppose a certain type of fertilizer has an expected yield per acre of mu 1 with variance sigma 2, whereas the expected yield fo
mart [117]

Answer:

See the proof below.

Step-by-step explanation:

For this case we just need to apply properties of expected value. We know that the estimator is given by:

S^2_p= \frac{(n_1 -1) S^2_1 +(n_2 -1) S^2_2}{n_1 +n_2 -2}

And we want to proof that E(S^2_p)= \sigma^2

So we can begin with this:

E(S^2_p)= E(\frac{(n_1 -1) S^2_1 +(n_2 -1) S^2_2}{n_1 +n_2 -2})

And we can distribute the expected value into the temrs like this:

E(S^2_p)= \frac{(n_1 -1) E(S^2_1) +(n_2 -1) E(S^2_2)}{n_1 +n_2 -2}

And we know that the expected value for the estimator of the variance s is \sigma, or in other way E(s) = \sigma so if we apply this property here we have:

E(S^2_p)= \frac{(n_1 -1 )\sigma^2_1 +(n_2 -1) \sigma^2_2}{n_1 +n_2 -2}

And we know that \sigma^2_1 = \sigma^2_2 = \sigma^2 so using this we can take common factor like this:

E(S^2_p)= \frac{(n_1 -1) +(n_2 -1)}{n_1 +n_2 -2} \sigma^2 =\sigma^2

And then we see that the pooled variance is an unbiased estimator for the population variance when we have two population with the same variance.

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3 years ago
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