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3 years ago

What is the smallest part of a compound that retains the properties of that compound?

1 answer:

5 0

"A molecule represents the smallest part into which a compound can be divided and still retain its chemical and physical properties" (socratic.org)

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Amestec 140 g solutie 9% cu 260 g solutie 12%, cu 60 g apa si x g solutie 4%. Ce c procentuala are noua solutie %?

Levart [38]

Answer:

PLEASE SOMEONE SOLVE THE QUESTION OR I'M GONNA FAIL

Explanation:

Purpose and Theory: A tablet of vitamin C contains the active ingredient called ascorbic acid (HC,H,0.).

Ascorbic acid is an organic acid which is a white power and is soluble in water.

In the following microtitration lab you will be grinding up a vitamin C tablet

, and using a 0.10 g sample of the

vitamin C powder, which will be dissolved in 20-40 mL of water. This solution will be used to determine the

quantity of ascorbic acid in a commercial vitamin C tablet.

Groups

Lab 2

# of Drops 1 or Drops 2 of Drops 3

Hadia

Data & Analysis:

Complete the missing information in the following data table [24]

Trial

Volume of NaOH (drops)

0 05mL drop

(NaOH (O 0050mol/L)

Volume of NaOH (ML)

Average Volume of NaOH (ml)

T I

O 0050

00050

The balanced chemical reaction between ascorbic acid and sodium hydroxide is:

HC,H,O + NaOH NaC,H,Oye H,O,

1. Stoichiometrically calculate the mass (in grams) of ascorbic acid in the powdered sample.

3 0

3 years ago

What volume in liters, l, of solution should sven prepare if he wants to make a 5.00 m solution using 210.0 grams, g, of sodium

weeeeeb [17]

To make a 5.00 M solution using 210.0 grams, g, of sodium chloride, NaCl, we will use the formula of volume of solution in liters is equal to mole of solute per molarity of solution, which is 0.718 L.

Molarity (M) refers to the amount of a substance in a specific volume of solution. It is defined as the moles of a solute per liters of a solution. Molarity is also known as the molar concentration of a solution.

Molarity is given by the quotient,

Molarity = moles of solute/volume of solution in liters.

Now in order to get the molarity of the solution, we have to divide the moles of solute over the liters of solution. Since we are given the mass of the solute, we must first convert the mass of NaCl into moles with the help of the molar mass of NaCl as a conversion factor.

210 NaCl x ( 1 mol NaCl/ 58.44g NaCl) = 3.59 mol NaCl.

We already have the molarity of the solution that is 5.00 M. So the solution to find out the volume will be,

Volume of solution in liters = mole of solute/ molarity of solution,

That is 3.59 mol NaCl / 5M = 0.718 L

To learn more about Molarity, head here

brainly.com/question/8732513

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5 0

2 years ago

Match the Terms to their definition:

olganol [36]

1. B
2. H
3. G
4. I
5. D
6. C
7. A
8. F
9. E
I am not sure weather it is correct but I wrote what I know

3 0

3 years ago

Read 2 more answers

Silver chloride, AgCl (Ksp = 1.8 x 10‒10), can be dissolved in solutions containing ammonia due to the formation of the soluble

Sergeeva-Olga [200]

Explanation:

The given reaction will be as follows.

$AgCl(s) \rightarrow Ag^{+}(aq) + Cl^{-}(aq)$ ............. (1)

$K_{sp}$ = $[Ag^{+}][Cl^{-}] = 1.8 \times 10^{-10}$

Reaction for the complex formation is as follows.

$Ag^{+}(aq) + 2NH_{3}(aq) \rightleftharpoons [Ag(NH_{3})_{2}]^{+}(aq)$ ........... (2)

$K_{f}$ = $\frac{[Ag(NH_{3})_{2}]}{[Ag^{+}][NH_{3}]^{2}} = 1.0 \times 10^{8}$

When we add both equations (1) and (2) then the resultant equation is as follows.

$AgCl(s) + 2NH_{3}(aq) \rightarrow [Ag(NH_{3})_{2}]^{+}(aq) + Cl^{-}(aq)$ ............. (3)

Therefore, equilibrium constant will be as follows.

K = $K_{f} \times K_{sp}$

= $1.0 \times 10^{8} \times 1.8 \times 10^{-10}$

= $1.8 \times 10^{-2}$

Since, we need 0.010 mol of AgCl to be soluble in 1 liter of solution after after addition of $NH_{3}$ for complexation. This means we have to set

$[Ag^{+}]$ = $[Cl^{-}]$

= $\frac{0.010 mol}{1 L}$

= 0.010 M

For the net reaction, $AgCl(s) + 2NH_{3}(aq) \rightarrow [Ag(NH_{3})_{2}]^{+}(aq) + Cl^{-}(aq)$

Initial : 0.010 x 0 0

Change : -0.010 -0.020 +0.010 +0.010

Equilibrium : 0 x - 0.020 0.010 0.010

Hence, the equilibrium constant expression for this is as follows.

K = $\frac{[Ag(NH_{3})^{+}_{2}][Cl^{-}]}{[NH_{3}]^{2}}$

$1.8 \times 10^{-2}$ = $\frac{0.010 \times 0.010}{(x - 0.020)^{2}}$

x = 0.0945 mol

or, x = 0.095 mol (approx)

Thus, we can conclude that the number of moles of $NH_{3}$ needed to be added is 0.095 mol.

3 0

4 years ago

The sum of two integers is -4. Can the two integers both be positive?

kaheart [24]

Answer: No.

Explanation: A negative integer can only be made with 2 negative integers or 1 positive and 1 negative integer.

3 0

3 years ago