The amount of 1,3-dimethyl urea produced would be 32,458 grams or 32.458 kg while that of carbon dioxide would be 16,214 grams of 16.214 kg
<h3>Stoichiometric problem</h3>
From the equation of the reaction, the mole ratio of methyl isocyanate with the products is 2:1 respectively.
Mole of 42,000 kg of methyl isocyanate = 42000/57 = 736.84 moles
Equivalent mole of 1,3-dimethyl urea = 736.84/2 =368.42 moles
Equivaent mole of carbon dioxide = 736.84/2 =368.42moles
Mass of 368.42 moles 1,3-dimethyl urea = 368.42 x 88.1 = 32,458 grams or 32.458 kg
Mass of 368.42 moles of carbon dioxide = 368.42 x 44.01 = 16,214 grams of 16.214 kg
More on stoichiometric problems can be found here: brainly.com/question/14465605
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3-B
4-C
5-A
6-A
7-C
8-B
9-A
10-B
Answer:
substrate concentration; one-half; the affinity of the substrate-enzyme interaction
Explanation:
The Michaelis constant, Km, refers to the substrate concentration at which a reaction proceeds at one-half of the maximum velocity. This constant most accurately reflects the affinity of the substrate-enzyme interaction.
You can look at the number of valence electrons and look at the size of the molecule itself to determine which element in this certain group is shown on the model.
