Answer: CuSO4>2-butanol> C4H9OH>C2H6>C3H8
Explanation:
Ionic substances are highly soluble in water. CuSO4 is an ionic salt composed of Cu2+ and SO42- ions. These ions are solvated in water hence the salt easily dissolves in the surrounding water molecules. this accounts for the fact that it is the most soluble of the five substances in water. 2-butanol contains the -OH group which interacts with water by hydrogen bonding. This accounts for the miscibility of alkanols with water in all proportions. however, this solubility in water decreases as the alky backbone increases. hence C4H9OH is less soluble in water that 2-butanol. Alkanes are usually not quite soluble in water but again solubility decreases with increase in the alky backbone hence propane is less soluble in water than ethane.
Hey there!
Molar mass of O3 = 47.9982 g/mol
therefore:
1 mole O₃ --------------------- 47.9982 g
moles O₃ ---------------------- 24 g
moles O₃ = 24 x 1 / 47.9982
moles O₃ = 24 / 47.9982
moles O₃ = 0.500 moles
Hope this helps!
The correct answer is D Elements
Types of matter are just different ways molecules behave at certain temperatures. There's no specific atoms or molecules that make solids, liquids, or gases. Ice, water, and water vapor are all H2O, for instance. The only correct answer would be that it is made of the same basic particles, but then again, so is everything.
<span>To determine the pH of the solution given, we make
use of the acid equilibrium constant (Ka) given. It is the ratio of the
equilibrium concentrations of the dissociated ions and the acid. The
dissociation reaction of the CH3COOH acid would be as follows:
</span>CH3COOH = CH3COO- + H+<span>
The acid equilibrum constant would be expressed as follows:
Ka = [H+][</span>CH3COO-] / [CH3COOH] = 1.8× 10^–5
<span>
To determine the equilibrium concentrations we use the ICE table,
CH3COOH H+ </span>CH3COO<span>-
I 1.60 0 0
C -x +x +x
----------------------------------------------------------------
E 1.60-x x x
</span>1.8× 10^–5 = [H+][CH3COO-] / [CH3COOH] <span>
1.8 x 10^-5 = [x][x] / [0.160-x] </span>
Solving for x,
x = 1.69x10^-3 = [H+] = [F-]
pH = -log [H+] = -log [1.69x10^-3] = 2.8
