Answer:
A. x = 58°
B. x = 10m
C. a = 44°
All approximated to nearest whole number.
Step-by-step explanation:
All triangles given are right angled triangles. Therefore, we would apply the trigonometry functions to solve for each missing side and angle.
Recall: SOHCAHTOA
a. Adjacent = 4.8cm,
Hypotenuse = 9cm
Angle to find =x°
Thus, we would apply the following formula:
Cos θ = Adjacent/Hypotenuse
Cos θ = 4.8/9 = 0.5333
θ = Cos-¹(0.5333) = 57.77
x ≈ 58° (to nearest whole number)
b. Opposite side = x
Hypothenuse = 40 m
Included angle = 14°
We would use:
Sine θ = opposite/hypothenuse
Sin (14) = x/40
Multiply both sides by 40
40*sin(14) = x
40*0.2419 = x
x = 9.676 = 10 m (to nearest whole number)
c. Opposite = 87mm
Adjacent = 91mm
θ = a°
We would use:
Tan θ = opposite/adjacent
Tan θ = 87/91
Tan θ = 0.9560
θ = tan-¹(0.9560)
θ = a = 43.71
a ≈ 44° (to nearest whole number)
L=2W+3, A=LW, using L from the first in the second gives you:
A=(2W+3)W
A=2W^2+3W, and we are told A=90 so
2W^2+3W=90
2W^2+3W-90=0
2W^2-12W+15W-90=0
2W(W-6)+15(W-6)=0
(2W+15)(W-6)=0, since W>0 for all real possibilities,
W=6ft, and since L=2W+3
L=15ft
So the pool will be 6 ft wide by 15 ft long.
Answer:
1.6x10^-18 gram
Step-by-step explanation:
(5.3 x 10⁻²³ gram/molecule) x (20,000 molecule)
= (5.3 x 10⁻²³ x 2 x 10⁴) gram
= (10.6 x 10⁻²³⁺⁴) gram
= (1.06 x 10⁻²³⁺⁵) gram
= 1.06 x 10⁻¹⁸ gram
We need to find the mass of 20,000 molecules of oxygen. It can be calculated using unitary method. Here, we can multiply 20,000 molecules by the mass of one oxygen molecule.
Answer:
なた方やタハアはワタは真綿は他和定や6
Step-by-step explanation:
15-x2/3627
So we take 6 out of each term so it is 
hope this helped.
