B. Conductors allow electricity to go through them only. Such as copper etc.
Answer:
a) ΔV = 20 V
, b) Q = 35.4 10⁻⁹ C, c) C = 1.77 10⁻⁹ F
Explanation:
a) The electric potential is
ΔV = E x
ΔV = 4.0 10⁵ 50 10⁻⁶
ΔV = 20 V
c) The capacity of a capacitor is
C = ε₀ A / d
The area of a square plate is
A = L²
A = 0.10²
A = 0.01 m²
L = 50mm = 50 10⁻⁶ m
Let's calculate
C = 8.85 10⁻¹² 0.01 /50 10⁻⁶
C = 1.77 10⁻⁹ F
b) the charge is
Q = C ΔV
Q = 1.77 10⁻⁹ 20
Q = 35.4 10⁻⁹ C
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Answer: D. decreasing the temperature
Explanation: