Question

This is a graph of a car speeding up and then reaching a constant speed of 12m /s. After it finishes speeding up, how far does the car travel during the last 6 seconds of the graph , from 4s to 10 s?

Answer 1

Answer:

After it finishes speeding up, the car goes 72 [m]

Explanation:

To solve this problem we must first understand the graphics. It is clear that in the last 6 seconds, that is, from the fourth to the tenth second, the car moves at a constant speed.

Therefore in this time interval, the car moves at a constant speed.

With the following equation of kinematics, we can calculate the distance traveled.

$x=x_{o}+v*t$

where:

x = final point [m]

x₀ = initial point [m]

v = constant velocity = 12 [m/s]

t = time = 6 [s]

Now replacing we have:

$x-x_{o} = 12*6\\x-x_{o}=72 [m]$