Question

The average person passes out at an acceleration of 7g (that is, seven times the gravitational acceleration on earth). suppose a car is designed to accelerate at this rate. how much time would be required for the car to accelerate from rest to 62.6 miles per hour? (the car would need rocket boosters!)

Answer 1

1g=32 ft per second ^2 62.6=330528ft 62.6 miles per hour =330528ft perhour=(330528ft perhour/3600seconds per hour)=91.8ft per second formula for the velocity (v(t))in feet per second at time t in seconds : v(t))=224t+v0,v0=initial velocity = 0ft per seconds v(t))=224t 224t =91.8 t=0.409seconds