Answer:
The velocity is ![v = 4.76 \ m/s](https://tex.z-dn.net/?f=v%20%3D%204.76%20%5C%20m%2Fs)
Explanation:
From the question we are told that
The first distance is ![d_1 = 4.0 \ km = 4000 \ m](https://tex.z-dn.net/?f=d_1%20%20%3D%20%204.0%20%5C%20km%20%20%3D%20%204000%20%5C%20m)
The first speed is ![v_1 = 5.0 \ m/s](https://tex.z-dn.net/?f=v_1%20%3D%20%205.0%20%5C%20m%2Fs)
The second distance is ![d_2 = 1.0 \ km = 1000 \ m](https://tex.z-dn.net/?f=d_2%20%20%3D%20%201.0%20%5C%20km%20%20%3D%20%201000%20%5C%20m)
The second speed is ![v_2 = 4.0 \ m/s](https://tex.z-dn.net/?f=v_2%20%20%3D%20%204.0%20%5C%20m%2Fs)
Generally the time taken for first distance is
![t_1 = \frac{d_1 }{v_1 }](https://tex.z-dn.net/?f=t_1%20%3D%20%20%5Cfrac%7Bd_1%20%7D%7Bv_1%20%7D)
![t_1 = \frac{4000}{5}](https://tex.z-dn.net/?f=t_1%20%3D%20%20%5Cfrac%7B4000%7D%7B5%7D)
![t_1 = 800 \ s](https://tex.z-dn.net/?f=t_1%20%3D%20%20800%20%5C%20s)
The time taken for second distance is
![t_1 = \frac{d_2 }{v_2 }](https://tex.z-dn.net/?f=t_1%20%3D%20%20%5Cfrac%7Bd_2%20%7D%7Bv_2%20%7D)
![t_1 = \frac{1000}{4}](https://tex.z-dn.net/?f=t_1%20%3D%20%20%5Cfrac%7B1000%7D%7B4%7D)
![t_1 = 250 \ s](https://tex.z-dn.net/?f=t_1%20%3D%20%20250%20%5C%20s)
The total time is mathematically represented as
![t = t_1 + t_2](https://tex.z-dn.net/?f=t%20%3D%20%20t_1%20%2B%20t_2)
=> ![t = 800 + 250](https://tex.z-dn.net/?f=t%20%3D%20%20800%20%2B%20250)
=> ![t = 1050 \ s](https://tex.z-dn.net/?f=t%20%3D%20%201050%20%5C%20s)
Generally the constant velocity that would let her finish at the same time is mathematically represented as
![v = \frac{d_1 + d_2}{t }](https://tex.z-dn.net/?f=v%20%3D%20%20%5Cfrac%7Bd_1%20%2B%20d_2%7D%7Bt%20%7D)
=> ![v = \frac{4000 + 1000}{1050 }](https://tex.z-dn.net/?f=v%20%3D%20%20%5Cfrac%7B4000%20%2B%201000%7D%7B1050%20%7D)
=> ![v = 4.76 \ m/s](https://tex.z-dn.net/?f=v%20%3D%204.76%20%5C%20m%2Fs)
Answer:
utrasonic
Explanation:
these are sounds beyond our hearing capacity range of 20-20kHz
Answer:
![F = 4.3671 * 10^{-8}\ Newtons](https://tex.z-dn.net/?f=F%20%3D%204.3671%20%2A%2010%5E%7B-8%7D%5C%20Newtons)
Explanation:
The gravitational force between two corpses is given by the following equation:
![F = GMm/d^2](https://tex.z-dn.net/?f=F%20%3D%20GMm%2Fd%5E2)
Where F is the force, G is the gravitational constant
(
), M and m are the masses of the corpses and d is the distance between them.
So we have that:
![F = 6.67408*10^{-11} * 7.1*10^4 * 73/89^2](https://tex.z-dn.net/?f=F%20%3D%206.67408%2A10%5E%7B-11%7D%20%2A%207.1%2A10%5E4%20%2A%2073%2F89%5E2)
![F = 4.3671 * 10^{-8}\ Newtons](https://tex.z-dn.net/?f=F%20%3D%204.3671%20%2A%2010%5E%7B-8%7D%5C%20Newtons)
The value of cos θ in the given figure is 0.98.
<h3>
What is cosine of an angle?</h3>
The cosine of an angle is defined as the sine of the complementary angle.
The complementary angle equals the given angle subtracted from a right angle, 90.
cos θ = sin(90 - θ)
For example, if the angle is 30°, then its complement is 60°
cos 30 = sin(90 - 30)
cos 30 = sin 60
0.866 = 0.866
<h3>Cosine of an angle with respect to sides of a right triangle</h3>
cos θ = adjacent side / hypotenuse side
adjacent side of the given right triangle is calculated as follows;
adj² = 10² - 2²
adj² = 100 - 4
adj² = 96
adj = √96
adj = 9.8
cos θ = 9.8/10
cos θ = 0.98
Thus, the value of cos θ in the given figure is 0.98.
Learn more about cosine of angles here: brainly.com/question/23720007
#SPJ1
Answer:
22 N applied force
Explanation: Since they are both pushing the wagon in the same direction the force adds up.