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Ede4ka [16]
3 years ago
5

A radioactive nucleus has a half-life of 5 x 108 years. Assuming that a sample of rock (say, in an asteroid) solidified right af

ter the solar system formed, approximately what fraction of the radioactive element should be left in the rock today?
Physics
1 answer:
Marina86 [1]3 years ago
5 0

Answer:

So the present mass will be 0.0017002 times of the initial mass of the sample.

Explanation:

Given:

  • half life of the given sample, t'=5\times 10^8\ yrs
  • We know that solar system came in to existence approximately 4.6\times 10^{9} years ago.

<u>Let the initial quantity on the formation of the solar system be, </u>m_o<u />

Then the final quantity at present be:

m=m_o\times (\frac{1}{2})^{(t/t')}

m=m_o\times (\frac{1}{2} )^{4.6\times 10^9\div(5\times 10^8)}

m=m_o\times 0.0017002

So the present mass will be 0.0017002 times of the initial mass of the sample.

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Qué ocurre con el espectro cuando se interpone el celofán de colores?
Travka [436]

Answer: You will only see the color that cellophane lets through

Explanation:

Let's begin by the fact the whole electromagnetic spectrum is known as "white light", which is composed by a range of colors (wavelengths).

Now, if we have a source with white light (the Sun, for example) and we interpose a cellophane of any color (let's choose red), this cellophane will act as a filter and will only let pass the color of the cellophane.

This is because the filter will absorb the other colors of the spectrum.

3 0
3 years ago
Consider a box sitting in the back of a pickup. The pickup accelerates to the right, and because the bed of the pickup is sticky
andreyandreev [35.5K]
The force would be coming from the right causing the box the lean/ slide to left, if it wasnt sticky.
8 0
3 years ago
How would you differentiate the theoretical and actual velocities of PE and KE in falling objects?
Solnce55 [7]

Answer: you've been trolled

Explanation:

8 0
3 years ago
Match the correct percentage of water to the correct phrase
Nesterboy [21]

Answer:

b

Explanation:

get a life <3

5 0
3 years ago
A spring of negligible mass stretches 3.00 cm from its relaxed length when a force of 7.50 N is applied. A 0.500-kg particle res
zhannawk [14.2K]

Answer:

a) 250 N/m

b) 22.4 rad/s , 3.6 Hz , 0.28 sec

c) 0.3125 J

Explanation:

a)

F = force applied on the spring = 7.50 N

x = stretch of the spring from relaxed length when force "F" is applied = 3 cm = 0.03 m

k = spring constant of the spring

Since the force applied causes the spring to stretch

F = k x

7.50 = k (0.03)

k = 250 N/m

b)

m = mass of the particle attached to the spring = 0.500 kg

Angular frequency of motion is given as

w = \sqrt{\frac{k}{m}}

w = \sqrt{\frac{250}{0.5}}

w = 22.4 rad/s

f = frequency

Angular frequency is also given as

w = 2 π f

22.4 = 2 (3.14) f

f  = 3.6 Hz

T = Time period

Time period is given as

T = \frac{1}{f}

T = \frac{1}{3.6}

T = 0.28 sec

c)

A = amplitude of motion = 5 cm = 0.05 m

Total energy of the spring-block system is given as

U = (0.5) k A²

U = (0.5) (250) (0.05)²

U = 0.3125 J

5 0
3 years ago
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