1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Ede4ka [16]
3 years ago
5

A radioactive nucleus has a half-life of 5 x 108 years. Assuming that a sample of rock (say, in an asteroid) solidified right af

ter the solar system formed, approximately what fraction of the radioactive element should be left in the rock today?
Physics
1 answer:
Marina86 [1]3 years ago
5 0

Answer:

So the present mass will be 0.0017002 times of the initial mass of the sample.

Explanation:

Given:

  • half life of the given sample, t'=5\times 10^8\ yrs
  • We know that solar system came in to existence approximately 4.6\times 10^{9} years ago.

<u>Let the initial quantity on the formation of the solar system be, </u>m_o<u />

Then the final quantity at present be:

m=m_o\times (\frac{1}{2})^{(t/t')}

m=m_o\times (\frac{1}{2} )^{4.6\times 10^9\div(5\times 10^8)}

m=m_o\times 0.0017002

So the present mass will be 0.0017002 times of the initial mass of the sample.

You might be interested in
A 0.500-kg object connected to a light spring with a spring constant of 20.0 N/m oscillates on a frictionless horizontal surface
givi [52]

Answer:

a = 0.009 J

b = 0.19 m/s

c = 0.005 J and 0.004 J

Explanation:

Given that

Mass of the object, m = 0.5 kg

Spring constant of the spring, k = 20 N/m

Amplitude of the motion, A = 3 cm = 0.03 m

Displacement of the system, x = 2 cm = 0.02 m

a

Total energy of the system, E =

E = 1/2 * k * A²

E = 1/2 * 20 * 0.03²

E = 10 * 0.0009

E = 0.009 J

b

E = 1/2 * k * A² = 1/2 * m * v(max)²

1/2 * m * v(max)² = 0.009

1/2 * 0.5 * v(max)² = 0.009

v(max)² = 0.009 * 2/0.5

v(max)² = 0.018 / 0.5

v(max)² = 0.036

v(max) = √0.036

v(max) = 0.19 m/s

c

V = ±√[(k/m) * (A² - x²)]

V = ±√[(20/0.5) * (0.03² - 0.02²)]

V = ±√(40 * 0.0005)

V = ±√0.02

V = ±0.141 m/s

Kinetic Energy, K = 1/2 * m * v²

K = 1/2 * 0.5 * 0.141²

K = 1/4 * 0.02

K = 0.005 J

Potential Energy, P = 1/2 * k * x²

P = 1/2 * 20 * 0.02²

P = 10 * 0.0004

P = 0.004 J

4 0
3 years ago
planet a has twice the mass of planet b. from this info what can we conclude about the acceleration due to gravity at the surfac
tangare [24]

Answer: acceleration due to gravity of planet a would be twice that of planet b. Given that the radius are thesame.

Explanation:

Acceleration due to gravity is as a result of the gravitational force of attraction of a planet to its centre.

g = GM/r^2

Where;

g = acceleration due to gravity

G = gravitational constant

M = mass of planet

r = radius of planet

Given that the two planet have the same radius, if the mass of planet a is twice the mass of planet b the the acceleration due to gravity of planet a would be twice that of planet b, because acceleration due to gravity is directly proportional to the mass of the planet.

6 0
3 years ago
Light travels in a straight line at a constant speed of 3,0 x 108 m/s for 4,1
zepelin [54]

Answer:

As the velocity of light is constant so the acceleration of the light is equal to zero.

a= dv/dt

Explanation:

4 0
3 years ago
Of all the planets in our solar system, Jupiter has the greatest gravitational strength. If a 1.5 kg pair of running shoes would
Andre45 [30]

Answer:

gₓ = 23.1 m/s²

Explanation:

The weight of an object is on the surface of earth is given by the following formula:

W = mg

where,

W = Weight of the object on surface of earth

m = mass of object

g = acceleration due to gravity on the surface of earth = strength of gravity on the surface of earth

Similarly, the weight of the object on Jupiter will be given as:

W_{x} = mg_{x}

where,

Wₓ = Weight of the object on surface of Jupiter = 34.665 N

m = mass of object = 1.5 kg

gₓ = acceleration due to gravity on the surface of Jupiter = strength of gravity on the surface of Jupiter = ?

Therefore,

34.65 N = (1.5 kg)g_{x}

g_{x} = \frac{34.65 N}{1.5 kg}

<u>gₓ = 23.1 m/s²</u>

7 0
3 years ago
Which was least likely to have been a component of Earth’s atmosphere before life began?
Otrada [13]
The answer to this question is a) sulfur
4 0
3 years ago
Read 2 more answers
Other questions:
  • When approaching an intersection where the traffic signal is out you should?
    7·1 answer
  • (PLEASE HELP) Which of the following describes a mixture?
    15·2 answers
  • After a group of researchers conducts a new experiment that has never been conducted before, what is the best way for other scie
    6·2 answers
  • Determine two ways power can be increased?
    12·2 answers
  • A round loop of wire carries a current of 100 A, has a radius of 10 cm, and its normal (vector) makes an angle of 30∘ with a mag
    12·1 answer
  • What is the most precise method for recording data points during an experiment? A. plotting the data point on an X-Y graph B. cr
    14·2 answers
  • A particle of mas 0.1 kg moves along the trajectory x(t)-3t t where x is in meters and t is in seconds. What is the kinetic ener
    8·1 answer
  • A truck is traveling due north at 50 km/hr approaching a crossroad. On a perpendicular road a police car is traveling west towar
    7·1 answer
  • A light wave has a wavelength of 0.015 m. What is the frequency of this light wave? (1 point)
    5·1 answer
  • When positive and negative charges are separated they want to...
    6·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!