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Anna11 [10]
2 years ago
7

3.3 by 2.5 + 5.7 by 2.5

Mathematics
1 answer:
den301095 [7]2 years ago
5 0

Answer:

22.5

Step-by-step explanation:

Using PEMDAS, we know that for expressions such as this, we're supposed to multiply before we add. This means that it should look something like this: (3.3 x 2.5) + (5.7 x 2.5). When you solve the multiplication first, you get 8.25 + 14.25. Solve, and you get 22.5. This problem can be solved using any basic calculator, or scratch paper!

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If f(x) = 6x - 4, what is f(x) when x = 8?
NNADVOKAT [17]
The answer is 44

To find this answer, we replace x with 8 and use PEMDAS (order of operations) to simplify

f(x) = 6*x - 4
f(8) = 6*8 - 4
f(8) = 48 - 4
f(8) = 44

4 0
3 years ago
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Ten friends want to play a game. They must be divided into three teams with three people in each team and one field judge. In ho
sertanlavr [38]

Answer:

It is the number of ways you can arrange the letters AAABBBCCCF, indicating that three players are on team A, three on team B, and three on team C, with one the field judge F.

Each different arrangement represents one of the ways you can form three teams of 3 with a field judge.

That number of arrangments, and therefore the number of ways to divide the players as required, is

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3 years ago
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Tan(43)-tan(13)/1+tan(43)tan(13)
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tan(13)-tan(2)

Step-by-step explanation:

= Monthsarry namin ng bebe ko

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3 years ago
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At 95% confidence, how large a sample should be taken to obtain a margin of error of 0.03 for the estimation of a population pro
Gnom [1K]

Answer:

A sample of 1068 is needed.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

The margin of error is:

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

95% confidence level

So \alpha = 0.05, z is the value of Z that has a pvalue of 1 - \frac{0.05}{2} = 0.975, so Z = 1.96.

At 95% confidence, how large a sample should be taken to obtain a margin of error of 0.03 for the estimation of a population proportion?

We need a sample of n.

n is found when M = 0.03.

We have no prior estimate of \pi, so we use the worst case scenario, which is \pi = 0.5

Then

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

0.03 = 1.96\sqrt{\frac{0.5*0.5}{n}}

0.03\sqrt{n} = 1.96*0.5

\sqrt{n} = \frac{1.96*0.5}{0.03}

(\sqrt{n})^{2} = (\frac{1.96*0.5}{0.03})^{2}

n = 1067.11

Rounding up

A sample of 1068 is needed.

8 0
2 years ago
Holler sold 150 frozen yogurts. Out of these frozen yogurts sold, 40% included toppings. How many frozen yogurts included toppin
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60. 40 percent of 150 yogurts comes to a sum of 60
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