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3 years ago

7

3.3 by 2.5 + 5.7 by 2.5

1 answer:

den301095 [7]3 years ago

5 0

Answer:

22.5

Step-by-step explanation:

Using PEMDAS, we know that for expressions such as this, we're supposed to multiply before we add. This means that it should look something like this: (3.3 x 2.5) + (5.7 x 2.5). When you solve the multiplication first, you get 8.25 + 14.25. Solve, and you get 22.5. This problem can be solved using any basic calculator, or scratch paper!

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The radius of a circle with an area of 60 square centimeters is represented by the expression √60/π centimeters. What is another

monitta

Answer:

r= 2 √(15/π)

Step-by-step explanation:

Given that :

Area of circle =60sq cm

radius=√60/π

$Area=\pi r^2\\60=\pi r^2\\\\\sqrt{\frac{60}{\pi}}=r\\\\\sqrt{\frac{15\times 4}{\pi}}=r\\2\sqrt{\frac{15}{\pi}}=r$

Hence the radius can be written as 2 √(15/π)

3 0

3 years ago

Does anyone know the correct choice for this question? If its correct ill mark you as the best answer choice! Please!

Alchen [17]

Answer:

the answer is H. it's slope is 5/4 which is the opposite reciprocal of -4/5 and that makes the lines perpendicular.

7 0

3 years ago

Solve for the indicated variable.

marta [7]

Answer:

Option (c) " $r=\dfrac{q}{4c}-h$ "

Step-by-step explanation:

The given equation is :

q = c4(h + r)

We need to solve it for r.

Dividing both sides of the given equation by 4c.

$\dfrac{q}{4c}=\dfrac{4c}{4c}(h+r)\\\\(h+r)=\dfrac{q}{4c}$

Now, subtract h both sides of the equation.

$h+r-h=\dfrac{q}{4c}-h\\\\r=\dfrac{q}{4c}-h$

Hence, this is the required solution.

3 0

3 years ago

What is the volume of a right pyramid with base area B=8ft^2 and height h=12 ft

vivado [14]

Answer:

The volume would be 31 cubic feet.

Step-by-step explanation:

To find this, use the formula for the area of a right pyramid.

A = 1/3bh

A = 1/3(8)(12)

A = 1/3(96)

A = 32

7 0

3 years ago

Can someone simplify8x + 5x please

igor_vitrenko [27]

Answer:

13x

because you would comibne like terms, so you add the 8 and 5.

6 0

3 years ago

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