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kari74 [83]
3 years ago
11

Degree of the polynomial (2x^3)-(x^2+11) .

Mathematics
1 answer:
WARRIOR [948]3 years ago
8 0

First, distribute the terms.

1(2x^3) = 2x^3

-1(x^2+11) = -x^2-11

Standard form:

2x^3 - x^2 - 11

Since there is a 3, the degree of polynomial is cubic.

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A rental car company charges $40 per day to rent a car and $0.08 for every
nikklg [1K]

Answer:

2000 miles.        

Step-by-step explanation:

If she has the car for  One day she can drive 2000 miles.

if she has the car for 2 days she can drive 1500

if she has the car for 3 days she can drive 1000

If she has the car for 4 days she can drive 500

8 0
2 years ago
Solve for m: (y_1 - y_2) = m(x_1 - x_2)
Mashutka [201]
y_1-y_2=m(x_1-x_2)\\
m=\dfrac{y_1-y_2}{x_1-x_2}
5 0
4 years ago
Plz hurry, brainliest and lots of points plz explain answer and only answer if you are actually gonna do it.
Citrus2011 [14]

Answer and Step-by-step explanation:

1st box:

0, -3

2nd box

-2, -9/4

3rd box:

2, -3/2

4th box:

4, 0

Btw 0, -2, 2, 4 are in the x-coordinate column if you didn’t know, and 1, -9/4, -3/2 are in the y-coordinate column

Basically to solve if you plug in 0 into x, so basically it’s 3(0)-4y=12, which you simplify gives you 0-4y=12, subtract 0 from 12 which is 12 and then do 12 divided by -4 and then you get y = -3 and that’s how you get the box answer

Idk how to the rest srry lol!

3 0
3 years ago
Will mark brainliest for 2 possible answers (WITH NO LINKS AND ANSWERS WITHOUT EXPLANATION)
Kamila [148]

Answer:

Equation in cubed form is x^3+7x^2+7x-15

Step-by-step explanation:

7 0
2 years ago
A set average city temperatures in August are normally distributed with a mean of 21.25 degrees Celsius and a standard deviation
Ainat [17]

Answer:

The proportion of temperatures that lie within the given limits are 10.24%

Step-by-step explanation:

Solution:-

- Let X be a random variable that denotes the average city temperatures in the month of August.

- The random variable X is normally distributed with parameters:

                           mean ( u ) = 21.25

                           standard deviation ( σ ) = 2

- Express the distribution of X:

                           X ~ Norm ( u , σ^2 )

                           X ~ Norm ( 21.25 , 2^2 )

- We are to evaluate the proportion of set of temperatures in the month of august that lies between 23.71 degrees Celsius and 26.17 degrees Celsius :

                           P ( 23.71 < X < 26.17 )

- We will standardize our limits i.e compute the Z-score values:

                          P (  (x1 - u) / σ < Z < (x2 - u) / σ )

                          P (  (23.71 - 21.25) / 2 < Z < (26.17 - 21.25) / 2  )

                          P ( 1.23 < Z < 2.46 ).

- Now use the standard normal distribution tables:

                          P ( 1.23 < Z < 2.46 ) = 0.1024

- The proportion of temperatures that lie within the given limits are 10.24%

4 0
3 years ago
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