Degree of the polynomial (2x^3)-(x^2+11) .

*Please Help* (There are more than 2 answers!)

GalinKa [24]

Look like both B and D are correct answers. because 23*400=9200 and 26*400=10400

4 0

3 years ago

A radio is being discounted 20% if the sale price of the radio is $51.44 what is the original price of the radio Radio is being

Grace [21]

Original price of the radio is $64.30

Sale price - $51.44
Discount rate - 20%

This means that $51.44 is the discounted price or is equivalent to 80% of the original price, since the 20% equivalent is deducted from the original price.

To get the original price, divide $51.44 by its corresponding percentage, 80%.

$51.44 / 80% = $64.30

To get the discount, multiply the original price by its discount rate

$64.30 x 20% = $12.86

To get the sales price, deduct the discount from the original price.

$64.30 - $12.86 = $51.44
100% - 20% = 80%

6 0

2 years ago

A business school has a goal that the average number of years of work experience of its MBA applicants is more than three years.

gizmo_the_mogwai [7]

Answer:

$z=\frac{3.1-3}{\frac{2.449}{\sqrt{47}}}=0.280$

$p_v =P(z>0.280)=0.390$

If we compare the p value and the significance level assumed $\alpha=0.01$ we see that $p_v>\alpha$ so we can conclude that we have enough evidence to fail reject the null hypothesis, so we can't conclude that the height of men actually its NOT significant higher than 0.3 at 1% of signficance.

Step-by-step explanation:

Data given and notation

$\bar X=3.1$ represent the sample mean

$\sigma=\sqrt{6}$ represent the sample standard deviation for the sample

$n=47$ sample size

$\mu_o =3$ represent the value that we want to test

$\alpha$ represent the significance level for the hypothesis test.

t would represent the statistic (variable of interest)

$p_v$ represent the p value for the test (variable of interest)

State the null and alternative hypotheses.

We need to conduct a hypothesis in order to check if the mean is higher than 3, the system of hypothesis would be:

Null hypothesis: $\mu \leq 3$

Alternative hypothesis: $\mu > 3$

If we analyze the size for the sample is > 30 and we know the population deviation so is better apply a z test to compare the actual mean to the reference value, and the statistic is given by:

$z=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}}$ (1)

z-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".

Calculate the statistic

We can replace in formula (1) the info given like this:

$z=\frac{3.1-3}{\frac{2.449}{\sqrt{47}}}=0.280$

P-value

Since is a one side test the p value would be:

$p_v =P(z>0.280)=0.390$

Conclusion

If we compare the p value and the significance level assumed $\alpha=0.01$ we see that $p_v>\alpha$ so we can conclude that we have enough evidence to fail reject the null hypothesis, so we can't conclude that the height of men actually its NOT significant higher than 0.3 at 1% of signficance.

3 0

2 years ago

Can some explain steps

Mashutka [201]

Answer:

r = 3.

Step-by-step explanation:

16 = 10 + √(3r + 27)

√(3r + 27) = 6

Square both sides:

3r + 27 = 36

3r = 36 - 27 = 9

r = 3.

Check the result:

Left side of the equation = 16

Right side = 10 + √(9 + 27)

= 10 + √36 = 16

5 0

2 years ago

Read 2 more answers

6. If n (E) = 40, n (A) = 22, n (ANB) = 8 and n ((AUB)') = 6, determine n(B)

Dimas [21]

Answer:

4

Step-by-step explanation:

First n(AUB)=n(E) - n((AUB)')

So n(AUB) = 40 - 6 = 34

Now all u hv to do is use the formulae,

n(AUB) = n(A) + n(B) - n(ANB)

So when u substitute above values,

34=22 + n(B) - 8

So,

n(B) = 4

4 0

3 years ago