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luda_lava [24]
3 years ago
9

What might happen if you got too close to the center of the Milky Way galaxy?

Chemistry
1 answer:
Lady_Fox [76]3 years ago
5 0

Answer:

you would be trapped in the gravitational pull of a black hole

Explanation:

there is a black hole in the center of the galacy

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Balance the following equation:
Firdavs [7]

Answer: a) 2K_2CrO_4+3Na_2SO_3+10HCl\rightarrow 4KCl+3Na_2SO_4+2CrCl_3+5H_2O

b) 1 mole of SO_2 is produced.

Explanation:

According to the law of conservation of mass, mass can neither be created nor be destroyed. Thus the mass of products has to be equal to the mass of reactants. The number of atoms of each element has to be same on reactant and product side. Thus chemical equations are balanced.

The skeletal equation is:

K_2CrO_4+Na_2SO_3+HCl\rightarrow KCl+Na_2SO_4+CrCl_3 +H_2O

The balanced equation will be:

2K_2CrO_4+3Na_2SO_3+10HCl\rightarrow 4KCl+3Na_2SO_4+2CrCl_3+5H_2O

Thus the coefficients are 2, 3 , 10 , 4 , 3 , 2 and 5.

b) Oxidation: 2I-^-\rightarrow I_2+2e-^-

Reduction: SO_4^{2-}+2e^-+4H^+\rightarrow SO_2+2H_2O

Net reaction:  2I-^-+SO_4^{2-}+4H^+\rightarrow I_2+SO_2+2H_2O

When 1 mole of I_2 is produced, 1 mole of SO_2 is produced.

8 0
3 years ago
A balanced chemical equation must have the same number of which of these on both sides of the equation?
andrew11 [14]
A balanced equation must have the same number of atoms on the both sides of equation.
4 0
3 years ago
Provide the structure of the major product which results from 1,4-addition of br2 to the diene shown below.
Vlad1618 [11]
The image provided shows the diene that is used for this question. We are told that the major product of the reaction is the 1,4-addition product. The result is the addition of a bromine atom to the first carbon and the fourth carbon of the diene. However, Br₂ can also add to just one alkene of the diene in a 1,2-addition to get the other product shown in the image.

As the first bromine atom adds to one of the alkenes, it adds to the first carbon which leads to the formation of a carbocation. The carbocation can be a stable tertiary center at the 2 carbon of the diene, or the less stable secondary center of the 4 carbon. To addition to the 4-carbon has a higher activation barrier which, but the product has a lower energy than the 1,2-product. Therefore, the 1,4-addition is the thermodynamic product and will form at higher temperatures. The 1,2-product is the kinetic product that will form at lower temperatures.

7 0
3 years ago
What kind of reaction is 2H202 → 2H20 + O2?
laiz [17]

Answer:

this reaction is so the answer should be A

5 0
3 years ago
When a soda can is dropped, it should not be immediately opened. Why? (A)The soda will squirt out because of decreased temperatu
igor_vitrenko [27]
C. the soda will squirt out because of increased agitation.
6 0
3 years ago
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