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solniwko [45]
2 years ago
7

A voltaic cell has a zinc anode and a copper cathode. They are connected by a wire but no salt bridge. What can you predict will

happen? A. Without a salt bridge to slow it down the reaction will occur faster than normal. B. The electrons will flow to the zinc anode where a negative charge will build up and eventually halt the reaction. C. None of these D. The electrons will flow to the copper cathode where a negative charge will build up and eventually halt the reaction.
Chemistry
1 answer:
Allisa [31]2 years ago
4 0

The prediction is that B. The electrons will flow to the zinc anode where a negative charge will build up and eventually halt the reaction.

<h3>What is zinc?</h3>

This is known as a chemical element, of the periodic table, that is essential to life and is one of the most widely used metals. Zinc is of considerable commercial importance.

Without the salt bridge, positive and negative charges will build up around the electrodes causing the reaction to stop.

Hence, we know that the purpose of the salt bridge is to keep the solutions electrically neutral and allow the free flow of ions from one cell to another.

Read more about<em> zinc</em> here:

brainly.com/question/25764334

#SPJ1

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pickupchik [31]

Answer:

pH = 4.25

Explanation:

A solution composed of a weak acid and its conjugate base is a <em>buffer solution</em>. To calculate the pH of a buffer solution we use the Henderson-Hasselbach equation:

pH = pKa + log ([conjugate base]/[weak acid]

In this case, we have the following data:

[conjugate base] = [sodium benzoate] = 0.230 M

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4 0
3 years ago
How many molecules are in 128g of H2O?
Lelechka [254]

Answer:

4.28x10^24 molecules

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3 years ago
a solution is prepared by dissolving 55g of CaCl2 into 300g of water. if the Kf of water is -1.86 c/m, shat is the freezing poin
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                T =

It is also known as depression between freezing point where, i is the Van't Hoff factor.

Let us assume that there is 100% dissociation. Hence, the value of i for these given species will be as follows.

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Depression in freezing point will have a negative sign. Therefore, d

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                 =

       

                  =

     

                   =

Therefore, we can conclude that given species are arranged according to their freezing point depression with the least depression first as follows.

                    Glucose < NaCl <

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