Answer:
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First convert the amount of grams you have of each substance to moles. Find your limiting reactant by calculating how many grams are needed to complete this reaction. If done correctly, you would see that we need .226 moles of Potassium to complete this reaction. However, we only have .118 moles of Potassium, so K must be our limiting reactant. Then use the moles of K to find out how many moles of K^2S are made. Then convert the amount of moles of K^2S to grams and you should get 10.3 g K^2S
Explanation:
You have a solution that contains 36 g HCl dissolved in 64 g water
Molar mass HCl = 36.45 g/mol
Mol HCl in 36 g = 36 g / 36.45 g/mol = 0.9876 mol
Molar mass H2O = 18 g/mol
Mol H2O in 64 g = 64 g / 18 g/mol = 3.5556 mol
Total mol = 0.9875 + 3.5556 = 4.5431 mol
Mol fraction HCl = 0.9876 mol / 4.5431 mol = 0.2174
Mol fraction H2O = 3.5556 / 4.5431 = 0.7826
The answer should have 2 significant digits:
Mol fraction HCl = 0.22
Mol fraction H2O = 0.78
Mol fraction has no units.
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Answer:
Ke = 34570.707
Explanation:
- H2(g) + Br2(g) → 2 HBr(g)
equilibrium constant (Ke):
⇒ Ke = [HBr]² / [Br2] [H2]
∴ [HBr] = (37.0 mol) / (2 L) = 18.5 mol/L
∴ [Br2] = (0.110 mol) / (2 L) = 0.055 mol/L
∴ [H2] = (0.360 mol) / (2 L) = 0.18 mol/L
⇒ Ke = (18.5 mol/L)² / (0.055 mol/L)(0.18 mol/L)
⇒ Ke = 34570.707
No elements visible!
Ions form between metals and non-metals.
Hope this helps!
