-13is negative and is 13 spaces away from 0. 15 is positive and is 15 spaces away from 0.
Solve each equation with (0, 3)
y = -x + 3
3 = -0 + 3
y = 3 (correct since y = 3 in (0, 3))
y = 2x - 3
3 = 2(0) - 3
3 = 0 - 3
3 = -3 (incorrect since it isn't equal)
So... No, because it does not check in the second equation.
Best of Luck!
Answer: the mode is 67.2
Step-by-step explanation:
Given that;
Data Frequency
30 - 34 1
35 - 39 0
40 - 44 3
45 - 49 7
50 - 54 5
55 - 59 10
60 - 64 10
65 - 69 21
70 - 74 12
Mode = ?
we know that mode is the number that has the highest number of appearance of frequency, so in this case, the data group that has the highest frequency (21) is 65 - 69
Lower class boundary of the modal group; L = 65
Frequency of the group before the modal group; Fm-1 = 10
Frequency of the modal group; Fm = 21
Frequency of the group after the modal group; Fm+1 = 12
Group width; G = 4
Now using the formula
Mode = L + [ (Fm - Fm-1) / ( (Fm - Fm-1) + (Fm - Fm+1) ) ] × W
so we substitute
Mode = 65 + [ (21 - 10) / ( (21 - 10) + (21 - 12) ) ] × 4
= 65 + [ 11 / 20] × 4
= 65 + 2.2
= 67.2
Therefore the mode is 67.2
The distance between 7 and -11 is 21