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3 years ago

12

Which could be the first step in simplifying this expression? Check all that apply. (x^3x^-6)^2

1 answer:

allsm [11]3 years ago

3 0

If the expression is what I understand it is, this is my answer. (x to the third times x to the negative sixth all squared)

First, i would simplify what is inside the parentheses. x^-6 is the equivalent to
1/x^6. Therefore, the expression inside the parentheses is a fraction: x^3/x^6.

When dividing numbers with exponents, just subtract the exponents.
3-6= -3 so the simplification of the expression in the parentheses is 1/x^3.

To finish the problem, I would apply the square from outside the parentheses to the values inside them. In this way, the exponent would be multiplied by 2.

Our final answer is 1/x^6.

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4/9 / 9/5= the answer is

mr Goodwill [35]

Answer:

20/81

Step-by-step explanation:

Without parentheses, it is hard to tell what you are dividing. We assume you want ...

(4/9)/(9/5)

Then ...

$\displaystyle\frac{\left(\frac{4}{9}\right)}{\left(\frac{9}{5}\right)}=\frac{4}{9}\cdot\frac{5}{9}=\frac{4\cdot 5}{9\cdot 9}=\frac{20}{81}$

_____

As written (without parentheses), your expression is evaluated left to right, so evaluates to ...

4/(9·9·5) = 4/405

7 0

3 years ago

The cost of movie tickets for a group of friends is $24. They buy 3 snacks. The cost of each snack us the same. The group spends

Bond [772]

Answer:

Answer is 6.5 dollars.

Step-by-step explanation:

Cost of movie tickets and snacks in total = 43.50

Cost of tickets = $24

Cost of Snacks = 43.50-24 =19.5$

number of snacks = 3

Cost of one snack = 19.5 ÷ 3 = 6.5$

4 0

2 years ago

(1+cos2x)/(1-cos2x) = cot^2x

sesenic [268]

We will turn the left side into the right side.

$\dfrac{1 + \cos 2x}{1 - \cos2x} = \cot^2 x$

Use the identity:

$\cos 2x = \cos^2 x - \sin^2 x$

$\dfrac{1 + \cos^2 x - \sin^2 x}{1 - ( \cos^2 x - \sin^2 x)} = \cot^2 x$

$\dfrac{1 - \sin^2 x + \cos^2 x }{1 - \cos^2 x + \sin^2 x} = \cot^2 x$

Now use the identity

$\sin^2 x + \cos^2 x = 1$ solved for sin^2 x and for cos^2 x.

$\dfrac{\cos^2 x + \cos^2 x }{\sin^2 x + \sin^2 x} = \cot^2 x$

$\dfrac{2\cos^2 x}{2\sin^2 x} = \cot^2 x$

$\dfrac{\cos^2 x}{\sin^2 x} = \cot^2 x$

$\cot^2 x = \cot^2 x$

8 0

3 years ago

6300/90???? PLS helpppp

dmitriy555 [2]

Answer: 70

Step-by-step explanation: 6300/90=70 Brainliest please?

4 0

3 years ago

How many centigrams are in 6 hectograms? Use the metric table to help answer the question.

Marta_Voda [28]

There are 60000 centigrams in 6 hectograms.

4 0

2 years ago

Read 2 more answers