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Naily [24]
3 years ago
12

Which could be the first step in simplifying this expression? Check all that apply. (x^3x^-6)^2

Mathematics
1 answer:
allsm [11]3 years ago
3 0
If the expression is what I understand it is, this is my answer. (x to the third times x to the negative sixth all squared)

First, i would simplify what is inside the parentheses. x^-6 is the equivalent to
1/x^6. Therefore, the expression inside the parentheses is a fraction: x^3/x^6.

When dividing numbers with exponents, just subtract the exponents. 
3-6= -3     so the simplification of the expression in the parentheses is 1/x^3.

To finish the problem, I would apply the square from outside the parentheses to the values inside them. In this way, the exponent would be multiplied by 2.

Our final answer is 1/x^6.
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$149.60 that's what he will have left

6 0
3 years ago
Compare the integers -13 and 15
agasfer [191]
-13is negative and is 13 spaces away from 0. 15 is positive and is 15 spaces away from 0.
6 0
3 years ago
Is (0, 3) a solution to the following system?
daser333 [38]

Solve each equation with (0, 3)

y = -x + 3

3 = -0 + 3

y = 3 (correct since y = 3 in (0, 3))

y = 2x - 3

3 = 2(0) - 3

3 = 0 - 3

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So... No, because it does not check in the second equation.

Best of Luck!

6 0
3 years ago
Find the measures of center for following. Data Frequency 30 - 34 1 35 - 39 0 40 - 44 3 45 - 49 7 50 - 54 5 55 - 59 10 60 - 64 1
dalvyx [7]

Answer: the mode is 67.2

Step-by-step explanation:

Given that;

Data               Frequency

30 - 34                 1

35 - 39                0

40 - 44                3

45 - 49                7

50 - 54                5

55 - 59               10

60 - 64               10

65 - 69              21

70 - 74               12

Mode = ?

we know that mode is the number that has the highest number of appearance of frequency, so in this case, the data group that has the highest frequency (21) is 65 - 69  

Lower class boundary of the modal group; L = 65

Frequency of the group before the modal group; Fm-1 = 10

Frequency of the modal group; Fm = 21

Frequency of the group after the modal group; Fm+1 = 12

Group width; G = 4

Now using the formula

Mode = L + [ (Fm - Fm-1) / ( (Fm - Fm-1) + (Fm - Fm+1) ) ] × W

so we substitute

Mode = 65 + [ (21 - 10) / ( (21 - 10) + (21 - 12) ) ] × 4

= 65 + [ 11 / 20] × 4

= 65 + 2.2

= 67.2    

Therefore the mode is 67.2

3 0
2 years ago
What is the distance between 7 and −11?
marta [7]
The distance between 7 and -11 is 21
4 0
3 years ago
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