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Naily [24]
3 years ago
12

Which could be the first step in simplifying this expression? Check all that apply. (x^3x^-6)^2

Mathematics
1 answer:
allsm [11]3 years ago
3 0
If the expression is what I understand it is, this is my answer. (x to the third times x to the negative sixth all squared)

First, i would simplify what is inside the parentheses. x^-6 is the equivalent to
1/x^6. Therefore, the expression inside the parentheses is a fraction: x^3/x^6.

When dividing numbers with exponents, just subtract the exponents. 
3-6= -3     so the simplification of the expression in the parentheses is 1/x^3.

To finish the problem, I would apply the square from outside the parentheses to the values inside them. In this way, the exponent would be multiplied by 2.

Our final answer is 1/x^6.
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What is -10=k+6 please show work thank you
Tresset [83]

Answer:

k=-16

Step-by-step explanation:

-10=k+6

subtract 6 both both sides to isolate the variable

-16=k

Happy Holidays!!

7 0
3 years ago
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Number 12. Find angle ADE
mr_godi [17]

Answer:

ADE=59º

Step-by-step explanation:

4x+15+13x+7=90

17x+22=90

17x=68

x=4

angle B=angle ADE so we plug in x=4 into 13x+7

13(4)+7=59º

5 0
3 years ago
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For every integer k from 1 to 10, inclusive the "k"th term of a certain sequence is given by (−1)(k+1)∗(12k). If T is the sum of
Katena32 [7]

Answer:

Option D. is the correct option.

Step-by-step explanation:

In this question expression that represents the kth term of a certain sequence is not written properly.

The expression is (-1)^{k+1}(\frac{1}{2^{k}}).

We have to find the sum of first 10 terms of the infinite sequence represented by the expression given as (-1)^{k+1}(\frac{1}{2^{k}}).

where k is from 1 to 10.

By the given expression sequence will be \frac{1}{2},\frac{(-1)}{4},\frac{1}{8}.......

In this sequence first term "a" = \frac{1}{2}

and common ratio in each successive term to the previous term is 'r' = \frac{\frac{(-1)}{4}}{\frac{1}{2} }

r = -\frac{1}{2}

Since the sequence is infinite and the formula to calculate the sum is represented by

S=\frac{a}{1-r} [Here r is less than 1]

S=\frac{\frac{1}{2} }{1+\frac{1}{2}}

S=\frac{\frac{1}{2}}{\frac{3}{2} }

S = \frac{1}{3}

Now we are sure that the sum of infinite terms is \frac{1}{3}.

Therefore, sum of 10 terms will not exceed \frac{1}{3}

Now sum of first two terms = \frac{1}{2}-\frac{1}{4}=\frac{1}{4}

Now we are sure that sum of first 10 terms lie between \frac{1}{4} and \frac{1}{3}

Since \frac{1}{2}>\frac{1}{3}

Therefore, Sum of first 10 terms will lie between \frac{1}{4} and \frac{1}{2}.

Option D will be the answer.

3 0
3 years ago
Sam invests £1800 in the bank for four
KIM [24]

Answer:

£2088

or

US$ 2,536.48 dollars (2021)

Step-by-step explanation:

4% of 1800 = 72

72 x 4 = 288

1800 + 288 = 2088

He has £2088 at the bank after 4 year

8 0
3 years ago
Find the 8th term of the geometric sequence 10, -40, 160, ...
mart [117]

Answer:

-163840

Step-by-step explanation:

3 0
3 years ago
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