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3 years ago

Can someone help me write this function? I've tried tons of equations but they don't work because of the 0:0. Thank you!

Mathematics

1 answer:

pav-90 [236]3 years ago

8 0

Just graph them. put the x number on the x-line and the y numbers on the y-line

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What is the measure of minor arc BD?

Vaselesa [24]

Answer:

$minor\ arc\ BD=100^o$

Step-by-step explanation:

The picture of the question in the attached figure

we know that

A circumscribed angle is the angle made by two intersecting tangent lines to a circle

In this problem

BC and CD are tangents to the circle

BC=CD ----> by the Two Tangent Theorem

That means

Triangle ABC and Triangle ADC are congruent

$m\angle BAC=m\angle DAC$

Find the measure of angle BAC

In the right triangle ABC

$m\angle BAC+m\angle BCA=90^o$

substitute given value

$m\angle BAC+40^o=90^o$

$m\angle BAC=90^o-40^o=50^o$

Find the measure of angle BAD

$m\angle BAD=2m\angle BAC$

$m\angle BAD=2(50^o)=100^o$

Find the measure of minor arc BD

we know that

$minor\ arc\ BD=m\angle BAD$ -----> by central angle

therefore

$minor\ arc\ BD=100^o$

8 0

3 years ago

Read 2 more answers

Help me please!!!!!!!!!!!!

GuDViN [60]

Answer:

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Step-by-step explanation:

;-;

4 0

2 years ago

If A(-5,7), B(-4,-5), C(-1,-6) and D(4,5) are the vertices of a quadrilateral, find the area of the quadrilateral ABCD.

MrMuchimi

After plotting the quadrilateral in a Cartesian plane, you can see that it is not a particular quadrilateral. Hence, you need to divide it into two triangles. Let's take ABC and ADC.

The area of a triangle with vertices known is given by the matrix
M = $\left[\begin{array}{ccc} x_{1}&y_{1}&1\\x_{2}&y_{2}&1\\x_{3}&y_{3}&1\end{array}\right]$

Area = 1/2· | det(M) |
= 1/2· | x₁·y₂ - x₂·y₁ + x₂·y₃ - x₃·y₂ + x₃·y₁ - x₁·y₃ |
= 1/2· | x₁·(y₂ - y₃) + x₂·(y₃ - y₁) + x₃·(y₁ - y₂) |

Therefore, the area of ABC will be:
A(ABC) = 1/2· | (-5)·(-5 - (-6)) + (-4)·(-6 - 7) + (-1)·(7 - (-5)) |
 = 1/2· | -5·(1) - 4·(-13) - 1·(12) |
 = 1/2 | 35 |
 = 35/2

Similarly, the area of ADC will be:
A(ABC) = 1/2· | (-5)·(5 - (-6)) + (4)·(-6 - 7) + (-1)·(7 - 5) |
 = 1/2· | -5·(11) + 4·(-13) - 1·(2) |
 = 1/2 | -109 |
 = 109/2

The total area of the quadrilateral will be the sum of the areas of the two triangles:

A(ABCD) = A(ABC) + A(ADC)
 = 35/2 + 109/2
 = 72

8 0

3 years ago

Any help is useful Equilateral triangle with a side of 16mm and was 155 mm long

zmey [24]

Answer:

Step-by-step explanation:

5 0

2 years ago

How do you factor 7+14

mote1985 [20]

You could factor a 7 out of 7 + 14 to get 7(1 + 2).

This would equal the same thing as 7 + 14, which is 21.

7 * 3 = 21.

21 can be factored like so:

1 * 21 = 21

3 * 7 = 21

5 0

3 years ago