Answer:
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Here we will use algebra to find three consecutive integers whose sum is 345. We start by assigning X to the first integer. Since they are consecutive, it means that the 2nd number will be X + 1 and the 3rd number will be X + 2 and they should all add up to 345. Therefore, you can write the equation as follows:
(X) + (X + 1) + (X + 2) = 345
To solve for X, you first add the integers together and the X variables together. Then you subtract three from each side, followed by dividing by 3 on each side. Here is the work to show our math:
X + X + 1 + X + 2 = 345
3X + 3 = 345
3X + 3 - 3 = 345 - 3
3X = 342
3X/3 = 342/3
X = 114
Which means that the first number is 114, the second number is 114 + 1 and the third number is 114 + 2. Therefore, three consecutive integers that add up to 345 are 114, 115, and 116.
114 + 115 + 116 = 345
We know our answer is correct because 114 + 115 + 116 equals 345 as displayed above.
Step-by-step explanation:
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(B) 8 less than the product of 3 and n
Here, we are given an equation 3n - 8
Let us consider each of the options one by one
(A) the product of 3, n and 8 will be written as 24n. Hence this isn't the correct answer.
(B) 8 less than the product of 3 and n will be written as 3n - 8. This matches our equation and hence is the correct answer.
(C) n minus 8 times 3 will be written as 24 - n. Hence, this is also incorrect.
(D) 3 times n less than 8 will be written as 8 - 3n. Thus, this is also eliminated.
Therefore, option B is the correct answer.
Learn more about expressing equations here-
brainly.com/question/4344214
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Answer:
x-int: 2
y-int: -2
Step-by-step explanation:
x-int is where the line crosses the x axis (horizontal line) and y-int is where the line crosses the y axis (vertical line).
Answer:
160
Step-by-step explanation:
- 8
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- 24
- 32
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- 48
- 56
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- 160
