2 years ago

Is 26,341 divisible by 9

Mathematics

1 answer:

Paul [167]2 years ago

6 0

No, it would leave a decimal

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Helppp please I will give brainliest <br><br>write an equation

Keith_Richards [23]

Answer:

Step-by-step explanation:

c=100g+50

then plug in g to get c values

8 0

2 years ago

I need help with this problem

Elis [28]

-32/1. Is the answer you just divide too and bottom by the bottom number which 3 is an common factor in both #,s

6 0

2 years ago

Pls help asap or else my parents will kill me eeeeeasy and explian for brainleest .

gtnhenbr [62]

Answer:

Step-by-step explanation:

I'm assuming that your "70=50x what is xx" actually means "find x if 70-50x = 0" If that's not what you meant, please retype your question.

Dividing both sides by -50 results in -70/50 + x = 0, and adding 70/50 to both sides results in x = 70/50, or 7/5.

Only if my assumptions are correct: x = 7/5.

3 0

2 years ago

Plug in 3 for the equation y=-x^2+12x-20

notka56 [123]

Step-by-step explanation:

y=(-x^2)+12x-20

=(-(3)^2)+12(3)-20

=(-9)+36-20

=16-9=7

y=7

I hope it helped you

8 0

1 year ago

If the endpoints of the diameter of a circle are (−8, −6) and (−4, −14), what is the standard form equation of the circle? A) (x

Andrei [34K]

Answer:

$\large\boxed{A.\ (x+6)^2+(y+10)^2=20}$

Step-by-step explanation:

The standard form of an equation of a circle:

$(x-h)^2+(y-k)^2=r^2$

(h, k) - center

r - radius

We have the endpoints of the diameter of a circle (-8, -6) and (-4, -14).

The midpoint of a diameter is a center of a circle.

The formula of a midpoint:

$\left(\dfrac{x_1+x_2}{2},\ \dfrac{y_1+y_2}{2}\right)$

Substitute:

$x=\dfrac{-8+(-4)}{2}=\dfrac{-12}{2}=-6\\\\y=\dfrac{-6+(-14)}{2}=\dfrac{-20}{2}=-10$

We have h = -6 and k = -10.

The radius is the distance between a center and the point on a circumference of a circle.

The formula of a distance between two points:

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Substitute (-6, -10) and (-8, -6):

$r=\sqrt{(-8-(-6))^2+(-6-(-10))^2}=\sqrt{(-2)^2+4^2}=\sqrt{4+16}=\sqrt{20}$

Finally we have

$(x-(-6))^2+(y-(-10))^2=(\sqrt{20})^2\\\\(x+6)^2+(y+10)^2=20$

5 0

3 years ago

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