Answer:
Step-by-step explanation:
AO = CO = radius
AO = CO ⇒ AB = BC and m∠AOB = m∠BOC = ¹/₂m∠AOC
From BDOE:
m∠EOB + m∠OBC + m∠CDE + m∠DEO = 360°
(65° + 75°) + 90° + x + 90° = 360°
140° + 180° + x = 360°
x = 40°
Detailed solution is given below in the attached image
Answer: 640
sum of interior angle of heptagon is 900°.
140°+148°+136°+150°+142°+90°+x=900°
806+x=900°
x=900°-806°
x=94°
hope that helps :)
