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3 years ago

What is the percent increase between 8,863,052 and 9,149,840?

Mathematics

2 answers:

katovenus [111]3 years ago

6 0

Answer:

=3.23577% increase

Step-by-step explanation:

1) subtract final value minus starting value

2) divide that amount by the absolute value of the starting value

3) multiply by 100 to get the percent increase

4) if the percentage bis negative, it means there was a decrease and not an increase

kvasek [131]3 years ago

4 0

Answer:

$increase = 9149840 - 8863052 \\ = 286788 \\ \% \: increase = \frac{286788}{8863052} \times 100\% \\ = 3.24\%$

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James, a real estate appraiser is looking at homes in the 78681 zip code. He takes a random sample of 42 homes form the Austin M

vazorg [7]

Answer:

80% confidence interval for the proportion of homes that are "eclectic" is [0.59 , 0.78].

Step-by-step explanation:

We are given that James takes a random sample of 42 homes form the Austin MLS (that's where Realtors go for information) and finds that 29 of them are listed as "eclectic" style.

Firstly, the pivotal quantity for 80% confidence interval for the population proportion is given by;

P.Q. = $\frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ~ N(0,1)

where, $\hat p$ = sample proportion of homes that are "eclectic" = $\frac{29}{42}$ = 0.69

n = sample of homes = 42

$\mu$ = population proportion of homes that are "eclectic"

<em>Here for constructing 80% confidence interval we have used One-sample z proportion statistics.</em>

<u>So, 80% confidence interval for the population proportion, p is ;</u>

P(-1.282 < N(0,1) < 1.282) = 0.80 {As the critical value of z at 10% level

of significance are -1.282 & 1.282}

P(-1.282 < $\frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ < 1.282) = 0.80

P( $-1.282 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ < ${\hat p-p}$ < $1.282 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ) = 0.80

P( $\hat p-1.282 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ < p < $\hat p+1.282 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ) = 0.80

<u>80% confidence interval for p</u> = [ $\hat p-1.282 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ , $\hat p+1.282 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ]

= [ $0.69-1.282 \times {\sqrt{\frac{0.69(1-0.69)}{42} } }$ , $0.69+1.282 \times {\sqrt{\frac{0.69(1-0.69)}{42} } }$ ]

= [0.59 , 0.78]

Therefore, 80% confidence interval for the proportion of homes that are "eclectic" is [0.59 , 0.78].

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3 years ago

How do I Solve 2-V=17

bonufazy [111]

Answer:

solution

-V=17-2

-V=15

8 0

3 years ago

Read 2 more answers

What is 9 divided by 350 original form

dlinn [17]

The answer is 38.8 repeating. Might as well just round it

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3 years ago

A bird flies from the bottom of a canyon that is 71 4/5 feet below sea level to a nest that is 875 7/10 feet above sea level. Wh

Rainbow [258]

The difference in elevation between the bottom of the canyon and the bird's nest is 947 1/2 feet

<h3>What is the difference in elevation between the bottom of the canyon and the bird's nest?</h3>

The given parameters are:

Nest = 71 4/5 feet above the seal level

Bottom of canyon = 875 7/10 below sea level

Below sea level means negative

So, we have:

Nest = 71 4/5 feet

Bottom of canyon = -875 7/10

The difference in elevation between the bottom of the canyon and the bird's nest is calculated as

Difference = |Nest - Bottom of canyon|

This gives

Difference = |71 4/5 - (-875 7/10)|

Evaluate the difference

Difference = |947 1/2|

Remove the absolute bracket

Difference = 947 1/2

Hence, the difference in elevation between the bottom of the canyon and the bird's nest is 947 1/2 feet