Answer:
y = 8x + 21
Step-by-step explanation:
Answer:
3.4625
Step-by-step explanation:
Given the equation:
Q(t)=0.05t^2 + 0.1t + 3.4 parts per million
Where t = time in years
By approximately how much will the carbon monoxide lvel change during the coming 6 months?
t = 6 months = 6/12 = 0.5 year
Q(0.5) = 0.05(0.5)^2 + 0.1(0.5) + 3.4 parts per million
Q(0.5) = 0.05(0.25) + 0.05 + 3.4
Q(0.5) = 0.0125 + 0.05 + 3.4
Q = 3.4625
Carbon monoxide level will change by approximately 3.4625 parts per million in 6 months
3p+2h=195
p + 15 = h
3p + 2(p + 15) = 195
3p + 2p + 30 = 195
5p = 165 (combine like terms and isolate your variable)
p = 33
33 + 15 = 48 (plug 33 into your original second equation)
ANSWER: 33 pretzels and 48 hotdogs
**You can plug these into your original (first) equation to check your answer
Answer:$9.49
Step-by-step explanation:
8.95×.61=5.4595
8.95×.45=4.0275
5.4595+4.0275= 9.49(rounded answer)
