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GREYUIT [131]
2 years ago
13

Suppose that a substance in a beaker is heated over a burner in a science lab. Which observation would most likely indicate that

a chemical change has occurred in the substance?
If the substance is a liquid or solid, an increase in temperature would indicate a chemical change.
If the substance is a liquid, a change of some of the liquid to gaseous form would indicate a chemical change.
If the substance is a solid, a change of some of the solid to liquid form would indicate a chemical change.
If the substance is a liquid or solid, production of an odor would indicate a chemical change.
Chemistry
2 answers:
saul85 [17]2 years ago
7 0

^^

Otherwise known as D.

(this is for people who are just looking for letters)

loris [4]2 years ago
5 0

Answer:

If the substance is a liquid or solid, production of an odor would indicate a chemical change.

Explanation:

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algol [13]

Answer:

9.0 moles of CaO

Explanation:

We have the reaction equation as follows;

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2 years ago
The temperature of a 95.4 g piece of Cu increases from 25.0 °C to 48.0 °C when the Cu absorbs 849 J of heat. What is the specifc
melisa1 [442]
<h3>Answer:</h3>

0.387 J/g°C

<h3>Explanation:</h3>
  • To calculate the amount of heat absorbed or released by a substance we need to know its mass, change in temperature and its specific heat capacity.
  • Then to get quantity of heat absorbed or lost we multiply mass by specific heat capacity and change in temperature.
  • That is, Q = mcΔT

in our question we are given;

Mass of copper, m as 95.4 g

Initial temperature = 25 °C

Final temperature = 48 °C

Thus, change in temperature, ΔT = 23°C

Quantity of heat absorbed, Q as 849 J

We are required to calculate the specific heat capacity of copper

Rearranging the formula we get

c = Q ÷ mΔT

Therefore,

Specific heat capacity, c = 849 J ÷ (95.4 g × 23°C)

                                        = 0.3869 J/g°C

                                        = 0.387 J/g°C

Therefore, the specific heat capacity of copper is 0.387 J/g°C

3 0
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Eva8 [605]
<span>Data:
pH = 5.2
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Knowing that: (</span><span>Equation to find the pH of a solution)</span>
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<span>
Solving:
</span>pH = -log[H+]
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Knowing that the exponential is the opposite operation of the logarithm, then we have:
[H+] = 10^{-5.2}
\boxed{\boxed{[H+] = 6.30*10^{-6}}}\end{array}}\qquad\quad\checkmark
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