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Anton [14]
3 years ago
5

In a similar experiment, unlabeled 4-butanolide was allowed to stand in an acidic solution in which the water had been labeled w

ith 180. When the lactone was extracted from the solution after four days, it was found to contain 180. Which oxygen of the lactone do you think became isotopically labeled?

Chemistry
1 answer:
Lina20 [59]3 years ago
6 0

Answer:

Please see attachment

Explanation:

Please see attachment

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What color do you get if you mix red and blue light?
andrezito [222]

Answer:

Purple light.

Yellow light.

Explanation:

5 0
2 years ago
Read 2 more answers
Is Pb(NO3)2 soluble or insoluble?
Sedaia [141]

Answer: it is soluble

Explanation: nitrates are soluble.

4 0
3 years ago
You have 15.42g of C2H6. How many moles of H2O can be made?
Amiraneli [1.4K]

<u>Answer:</u> The moles of water produced are 1.54 moles.

<u>Explanation:</u>

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}

Given mass of ethane = 15.42 g

Molar mass of ethane = 30.07 g/mol

Putting values in above equation, we get:

\text{Moles of ethane}=\frac{15.42g}{30.07g/mol}=0.513mol

The chemical equation for the combustion of ethane follows:

2C_2H_6+5O_2\rightarrow 4CO2+6H_2O

By Stoichiometry of the reaction:

2 moles of ethane produces 6 moles of water

So, 0.513 moles of ethane will produce = \frac{6}{2}\times 0.513=1.54mol of water

Hence, the moles of water produced are 1.54 moles.

4 0
3 years ago
A 40.0-L sample of fluorine is heated from 90.0°C to 186.0°C. What volume will the sample occupy at the higher temperature?
jasenka [17]

Answer:

The volume will be 82.67 L

Explanation:

Charles's Law is the relationship between the volume and temperature of a certain amount of ideal gas. In this way, Charles's law is a law that says that when the amount of gas and pressure are kept constant, the ratio between volume and temperature will always have the same value:

\frac{V}{T} = k

Having a certain volume of gas V1 that is at a temperature T1 at the beginning of the experiment, by varying the volume of gas to a new value V2, then the temperature will change to T2, and it will be true:

\frac{V1}{T1} =\frac{V2}{T2}

In this case, you know:

  • V1= 40 L
  • T1= 90 °C
  • V2= ?
  • T2= 186 °C

Replacing:

\frac{40L}{90C} =\frac{V2}{186 C}

Solving:

V2=\frac{40L}{90C} *186 C

V2= 82.67 L

<u><em>The volume will be 82.67 L</em></u>

5 0
3 years ago
5) Some students believe that teachers are full of hot air. If I inhale 2.2 liters of gas at a temperature of 180 C and it heats
ahrayia [7]

Given :

If I inhale 2.2 liters of gas at a temperature of 180 C and it heats to a temperature of 380 C in my lungs.

To Find :

The new volume of the gas.

Solution :

Since, their is no information about pressure, so we will assume that pressure is constant.

We know, relation between temperature and volume in constant pressure is :

\dfrac{V_1}{T_1}=\dfrac{V_2}{T_2}

Putting all given values in above equation, we get :

V_2 = \dfrac{V_1\times T_2}{T_1}\\\\V_2 = \dfrac{2.2\times (180+273)}{(380+273)}\\\\V_2 = 1.53 \ liters

Hence, this is the required solution.

8 0
3 years ago
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