Answer:
The answer is all of the above
Explanation:
Sound has waves which are compression waves and those waves transfer into energy molecules. Sound is heard by human ears. Sound waves can behave in predictable ways. All sound requires a medium through to travel
Answer:
56.9 mmoles of acetate are required in this buffer
Explanation:
To solve this, we can think in the Henderson Hasselbach equation:
pH = pKa + log ([CH₃COO⁻] / [CH₃COOH])
To make the buffer we know:
CH₃COOH + H₂O ⇄ CH₃COO⁻ + H₃O⁺ Ka
We know that Ka from acetic acid is: 1.8×10⁻⁵
pKa = - log Ka
pKa = 4.74
We replace data:
5.5 = 4.74 + log ([acetate] / 10 mmol)
5.5 - 4.74 = log ([acetate] / 10 mmol)
0.755 = log ([acetate] / 10 mmol)
10⁰'⁷⁵⁵ = ([acetate] / 10 mmol)
5.69 = ([acetate] / 10 mmol)
5.69 . 10 = [acetate] → 56.9 mmoles
The combined gas law equation has been
.
The combined gas law has been assigned to the ideal gas. It has been stating that ideal gas are having negligible inter-molecular attraction and collision resulting in the absence of pressure and volume from the particles.
In an ideal gas the equation has been given as:

Where, <em>P </em>has been the pressure of the gas
<em>V </em>has been the volume of the gas
<em>n </em>has been the moles of the gas
<em>R </em>has been a constant
<em>T </em>has been the temperature of the gas
The combined gas law has been given as the change in the pressure, and volume for a gas. It has been given as:

For more information about combined gas law, refer to the link:
brainly.com/question/13154969
If he was 30.8% too low, it means that he was at 69.2% of the boiling point needed. So 50o C is 69.2% of total.
In order to know what 100% is, you can divide the number by it's percentage and then multiply it by a hundred.
So: 50/30.8=1.623
1.623*100=162.3
So the correct boiling point of the liquid he was working with in the lab is 162.3 oC