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leonid [27]
3 years ago
5

State the Constituents of the following alloys:magnalium and bronze​

Chemistry
1 answer:
____ [38]3 years ago
8 0
Magnalium: Magnesium and Aluminum

Bronze: Copper, Tin, Arsenic, Phosphorus, Aluminum, Manganese and Silicon (whichever you learned in class from those)
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Which of the following is a correct Lewis structure?
ololo11 [35]

Answer:

The answer to your question is letter B

Explanation:

a. [: C≡C :]   This option is not correct because Carbon only has 4 valence electrons and carbons in this structure have 5, this structure does not exist.

b. [: N≡N :]  This option is correct because because Nitrogen has 5 valence electrons and this structure shows that number of electrons.

c. No right choice. This option is incorrect because letter B is correct.

8 0
3 years ago
Read 2 more answers
Write the oxidation number for the following elements: for brainliest answer
ollegr [7]

Explanation:

Here's an oxidation chart to help

..................

6 0
3 years ago
Which of the following molecules nonpolar?
kap26 [50]

Answer:

CHC13

Explanation:

4 0
4 years ago
The heat of combustion (∆H) for an unknown hydrocarbon is -8.21 kJ/mol. If 0.424 mol of the hydrocarbon is burned in a bomb calo
klio [65]

When 0.424 moles of an unknown hydrocarbon (∆Hc = -8.21 kJ/mol) is burned in a bomb calorimeter (C = 1.12 kJ/°C), the change in the temperature is 3.10 °C.

The heat of combustion (∆Hc) for an unknown hydrocarbon is -8.21 kJ/mol. The heat released by the combustion of 0.424 moles of the hydrocarbon is:

Qc = 0.424 mol \times \frac{(-8.21kJ)}{mol} = -3.48 kJ

According to the law of conservation of energy, the sum of the heat released by the combustion (Qc) and the heat absorbed by the bomb calorimeter (Qb) is zero.

Qc + Qb = 0\\\\Qb = -Qc = 3.48 kJ

Given the heat absorbed by the bomb calorimeter (Qb) and the heat capacity of the bomb calorimeter (C), we can calculate the temperature change (ΔT) using the following expression.

Qb = C \times \Delta T\\\\\Delta T = \frac{Qb}{C} = \frac{3.48 kJ}{1.12 kJ/\° C } = 3.10 \° C

When 0.424 moles of an unknown hydrocarbon (∆Hc = -8.21 kJ/mol) is burned in a bomb calorimeter (C = 1.12 kJ/°C), the change in the temperature is 3.10 °C.

Learn more: brainly.com/question/24245395

8 0
3 years ago
When dynamic equilibrium is achieved, the rate of the forward and backward reactions go to zero. (T&F)
ratelena [41]

Answer:

1) False

2) there are equal amounts of rectants and products

Explanation:

1)  When dynamic equilibrium is achieved. the rate of forward and backward reaction they are the same, that is to say, two opposite reactions occur at the same rate, keeping the concentrations constant over time.  Different to say the rate of the ractions go to zero.

2)  A chemical equilibium exists when what is produce in quantities is equal to what reacts.

So the correct answer is the literal (d).

5 0
3 years ago
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