From the Boyle's law, it is clear that volume is inversely proportional to pressure. Thus it is prudent to say that, P1V1=P2V2
From the question above,
P1=1atm
P2=3.8atm
V1=?
V2=7.6L
Hence, 1*V1=3.8atm*7.6L
V1=28.88L
Explanation:
Substances generally tends to specialize as either oxidizing or reducing agents.
An oxidizing agent is an electron acceptor which causes a co-reactant to be oxidized in a reaction.
Examples are:
Non-metals especially oxygen and the halogens.
Other examples are H₂SO₄ , HNO₃, KMnO₄, K₂Cr₂O₇
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A homogeneous mixture is uniform throughout, like water that has dissolved gases. You cannot easily distinguish the individual parts of the mixture. Many other drinks are considered homogeneous too. Laundry detergent and colognes are other examples of homogeneous mixtures. Homogeneous mixtures can also be a solid (ie. steel), liquid or gas form. It does not always have to be a liquid.
Answer:
8.11g
Explanation:
Given parameters:
Molarity of aqueous solution = 0.3M
total volume = 0.15L
Molecular weight of glucose = 180.6g/mol
Unknown:
Mass of glucose needed in the solution = ?
Solution:
To solve this problem, we need to understand molarity.
Molarity is the number of moles of solute in a given volume of solution. In this problem, the solute here is the glucose and the solvent is water.
Molarity = 
A solution is made up of solute and solvent.
now, let us solve for the number of moles of the solute which is glucose;
Number of moles of glucose = molarity x volume of solution;
= 0.3 x 0.15
= 0.045mole
Now to find the mass of glucose;
mass of glucose = number of moles x molar mass
input the parameters;
Mass of glucose = 0.045 x 180.16 = 8.11g
Answer:
o increase the rate of chemical reaction
Explanation:
Enzymes are chemical catalysts that speed up chemical reactions by lowering their activation energy. Enzymes have an active site with a unique chemical environment that fits particular chemical reactants for that enzyme, called substrates. Enzymes and substrates are thought to bind according to an induced-fit model.
