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3 years ago

the Rockets lost three of the 20 games played this season what fraction of the game did the Rockets lose?

Mathematics

1 answer:

Marat540 [252]3 years ago

4 0

Answer:

So I add 20** First , & took away 3 because it says the rocket lost 3 of the 20** Games , & he lost 17 if you take away it you will have to do 3-20 & you will get _17

Step-by-step explanation:

20-3 =17 he lost 17 .

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Secants AC and DB intersect at point E inside the circle. Given that the measure of arc CD = 40o, arc AB = 60o, and arc BC = 160

s344n2d4d5 [400]

Answer:

C. $130^{\circ}$

Step-by-step explanation:

Please find the attachment.

We have been given that secants AC and DB intersect at point E inside the circle. Given that the measure of arc $CD = 40^o$ , arc $AB = 60^o$ , and arc $BC = 160^o$ . We are asked to find the measure of angle AED.

We know that the measure of angle formed by two intersecting secants is half the sum of measure of the arcs by intercepted by the angle and its vertical angle.

$\angle AED=\frac{\widehat{BC}+\widehat{AD}}{2}$

Let us find measure of arc AD by subtracting measure of given arcs from 360 degrees as:

$\widehat{AD}=360^{\circ}-(60^{\circ}+40^{\circ}+160^{\circ})$

$\widehat{AD}=360^{\circ}-(260^{\circ})$

$\widehat{AD}=100^{\circ}$

$\angle AED=\frac{160^{\circ}+100^{\circ}}{2}$

$\angle AED=\frac{260^{\circ}}{2}$

$\angle AED=130^{\circ}$

Therefore, measure of angle AED is 130 degrees and option C is the correct choice.

6 0

3 years ago

The probability that a randomly selected 3-year-old male chipmunk will live to be 4 years old is 0.96516.

mezya [45]

Using the binomial distribution, it is found that there is a:

a) The probability that two randomly selected 3-year-old male chipmunks will live to be 4 years old is 0.93153 = 93.153%.

b) The probability that six randomly selected 3-year-old male chipmunks will live to be 4 years old is 0.80834 = 80.834%.

c) The probability that at least one of six randomly selected 3-year-old male chipmunks will not live to be 4 years old is 0.19166 = 19.166%. This probability is not unusual, as it is greater than 5%.

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For each chipmunk, there are only two possible outcomes. Either they will live to be 4 years old, or they will not. The probability of a chipmunk living is independent of any other chipmunk, which means that the binomial distribution is used to solve this question.

Binomial probability distribution

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$C_{n,x} = \frac{n!}{x!(n-x)!}$

The parameters are:

x is the number of successes.
n is the number of trials.
p is the probability of a success on a single trial.

In this problem:

0.96516 probability of a chipmunk living through the year, thus $p = 0.96516$

Item a:

Two is P(X = 2) when n = 2, thus:

$P(X = 2) = C_{2,2}(0.96516)^2(1-0.96516)^{0} = 0.9315$

The probability that two randomly selected 3-year-old male chipmunks will live to be 4 years old is 0.93153 = 93.153%.

Item b:

Six is P(X = 6) when n = 6, then:

$P(X = 6) = C_{6,6}(0.96516)^6(1-0.96516)^{0} = 0.80834$

The probability that six randomly selected 3-year-old male chipmunks will live to be 4 years old is 0.80834 = 80.834%.

Item c:

At least one not living is:

$P(X < 6) = 1 - P(X = 6) = 1 - 0.80834 = 0.19166$

The probability that at least one of six randomly selected 3-year-old male chipmunks will not live to be 4 years old is 0.19166 = 19.166%. This probability is not unusual, as it is greater than 5%.

A similar problem is given at brainly.com/question/24756209

6 0

3 years ago

Solve for x: <br> (X+5)^1/2 = (5-2x)^1/4

Greeley [361]

Answer:

X = Negative 2 (-2)

7 0

4 years ago

Pleassssssssssssssssssssse HELP QUICKLY PLEASSSSSSE

Ierofanga [76]

Answer:

7/6 or A

Step-by-step explanation:

2/3(9-6)-5/6= 7/6

6 0

3 years ago

A supermarket sells two flavors of cereal: a fruit flavor and a chocolate flavor. In a market survey, the event that a customer

Sedaia [141]

This is a binomial distribution.
p = 0.71, q = 1 - p = 1 - 0.71 = 0.29, n = 20

P(x ≤ 19) =1 - P(x = 20) = 1- 20C20 x (0.71)^(20 - 20) x (0.29)^20 = 1 - 0.29^20 = 1 - 0 = 1

4 0

4 years ago