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seraphim [82]
3 years ago
13

PLEASE HELP ME WITH THIS MATH TEST

Mathematics
2 answers:
Alex3 years ago
5 0

Answer:

40cm²

Step-by-step explanation:

just need to add all the 1cm² together to get 40

Troyanec [42]3 years ago
4 0

Answer: 40 cm ^2

Step-by-step explanation:

cuz math

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Math I need help wit this problem
beks73 [17]
0, sqrt(9), 16.00, -4, -2, and -5 are all whole numbers because they all simplify to numbers without decimals
6 0
3 years ago
Jon recently drove to visit his parents who live 270 270 miles away. On his way there his average speed was 24 24 miles per hour
Ber [7]

Answer:

He drove there at 60 mph, and he drove back at 36 mph.

Step-by-step explanation:

one way distance = d = 270 miles

average speed on way back = s

average speed on the way there = s + 24

time driving there = t

time driving back = 12 - t

average speed = distance/time

distance = speed * time

going there:

270 = (s + 24)t

270 = st + 24t

going back

270 = s(12 - t)

270 = 12s - st

We have a system of equations:

270 = st + 24t

270 = 12s - st

Solve the first equation for t.

t(s + 24) = 270

t = 270/(s + 24)

Substitute in the second equation.

270 = 12s - s[270/(s + 24)]

270 = 12s - 270s/(s + 24)

Multiply both sides by s + 24.

270s + 6480 = 12s^2 + 288s - 270s

12s^2 - 252s - 6480 = 0

Divide both sides by 12.

s^2 - 21s - 540 = 0

(s - 36)(s + 15) = 0

s = 36 or s = -15

The average speed cannot be negative, so we discard the solution s = -15.

s = 36

s + 24 = 60

Answer: He drove there at 60 mph, and he drove back at 36 mph.

3 0
3 years ago
What is the circumference of the circle of a diameter of 12​
KiRa [710]

Answer: C≈37.7  

thats my answer

5 0
3 years ago
Read 2 more answers
What are the x-intercept and the y-intercept of the graph 3x - 2y =
padilas [110]
To find the answer you must know what 3x - 2y=
7 0
3 years ago
Suppose an isosceles triangle abc has a=pi/4 and b=c=4. What is the length of a^2?
Zanzabum

The law of cosines states that, if \alpha is the angle between sides b and c,

a^2 = b^2+c^2-2bc\cos(\alpha)

So, plugging our values, we have

a^2 = 16+16-2\cdot 4\cdot 4\cdot\cos\left(\dfrac{\pi}{4}\right)

This is equal to

a^2 = 32-32\cdot\dfrac{\sqrt{2}}{2} = 32-16\sqrt{2}

3 0
3 years ago
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