The answer is A.
Which is... KCI
Fractional distillation is used for the refining of crude petroleum.
<h3>How are the components of
crude petroleum separated out?</h3>
Fractional distillation is the procedure used to separate crude oil's numerous constituents.
- A mixture is divided into several components, known as fractions, using fractional distillation.
- A combination of hydrocarbons makes up crude oil. The crude oil evaporates, and in the fractionating column, its vapors condense at various temperatures.
- The hydrocarbon molecules in each percent have a comparable number of carbon atoms and a comparable range of boiling points.
- The mixture is placed above a tall fractionating column that has multiple condensers coming off at various heights.
- The bottom of the column is warm, while the top is cool. High boiling point compounds condense at the bottom, whereas low boiling point substances condense as they ascend.
Learn more about fractional distillation here:
brainly.com/question/15187318
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Answer:
This is because of scintillation ("Twinkling") as the light passes through the atmosphere of the Earth. As the air moves in and out, the starlight is refracted, often different colors in different directions. Because of this "chromatic abberation," stars can appear to change colors when they are twinkling strongly.
Explanation:
Answer:
2.15
Explanation:
For this question, we have to remember the <u>pH formula</u>:
![pH~=~-Log[H_3O^+]](https://tex.z-dn.net/?f=pH~%3D~-Log%5BH_3O%5E%2B%5D)
By definition, the pH value is calculated when we do the -Log of the concentration of the <u>hydronium ions</u> (
). So, the next step is the calculation of the <u>concentration</u> of the hydronium ions. For this, we have to use the <u>molarity formula</u>:

We already know the number of moles (0.0231 moles) and the volume (3.33 L). So, we can plug the values into the molarity formula:

With this value, now we can calculate the pH value:
![pH~=~-Log[0.00693~M]~=~2.15](https://tex.z-dn.net/?f=pH~%3D~-Log%5B0.00693~M%5D~%3D~2.15)
<u>The pH would be 2.15</u>
I hope it helps!