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saw5 [17]
3 years ago
7

The specific rotation of (S)-2-butanol is +13.5. If 0.119 g of its enantiomer is dissolved in 10.0 mL of ethanol and

Chemistry
1 answer:
larisa86 [58]3 years ago
7 0

Answer:

+15.8°

Explanation:

The formula for the observed rotation (α) of an optically active sample is

α = [α]<em>lc </em>

where

<em>l</em> = the cell path length in decimetres

<em>c</em> = the concentration in units of g/100 mL

[α] = the specific rotation in degrees  

1. Convert the concentration to units of g/100 mL

c = \frac{\text{0.119 g}}{\text{10.0 mL}} \times \frac{10 }{10 } =\frac{\text{1.19 g}}{\text{100 mL}}

2. Calculate the observed rotation

\alpha = (+13.3 ^{\circ}) \times 1.19 \times 1 = +15.8^{\circ}

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