Answer:
C5H6N2O3
Explanation:
First the empirical formulas
C= 41.8÷12= 2.48
H= 4.7÷1= 4.7
O= 37.3÷ 16= 2.33
N= 16.3÷14 = 1.16
Divide by the smallest
C= 3.48/1.16=3
H= 4.7/1.16=4.1
O= 2.33/1.16=2
N= 1.16/1.16=1
Therefore empirical formula = C3H4NO2
To calculate molecular formula for osmotic pressure,
π= cRT
Or
π=cgRT/M where cg is in g/liter & T is temperature in Kelvin. Thus
π= (7.480*0.0821*300)/ M
M= 184.23/1.43
M= 128.83
To find molecular Formula
Molecular Mass= (empirical mass)n
128.83= (C3H4NO2)n
128.83= 86n
n= 1.5
Therefore the molecular formula
(C3H4NO2)1.5
= C4.5H6N1.5O3
Approximately
C5H6N2O3
The correct answer is A: Vapor pressure lowering.
Certain properties in chemistry are called colligative properties. These colligative properties depends on the amount of solute present.
Examples of colligative properties include;
- Vapor pressure lowering
- Freezing point depression
- Boiling point elevation
- Osmotic pressure
When a solute is introduced into water, the vapour pressure of water is lowered.
Hence, when KI is added to a sample of water, vapor pressure lowering occurs.
brainly.com/question/10323760
Explanation:
If we change the concentration of Potassium since we take KI solution, concentration of I- changes, then the rate changes accordingly
Rate = k[H2O2 ]^a[I-]^b [H+]^c
The concentrations of I- and H+ are held constant in the procedure
thus to study the rate of the reaction, concentration of KI solution has to be constant only the peroxide solution varies.
Answer:
How can drying a hydrate help you determine its mole ratio of water to salt?
Explanation:
