What is the oxidation number of phosphorus (P) in sodium phosphate (Na3PO4)?
2 answers:
Na⁺¹₃P⁺⁵O⁻²₄
+1*3 + (+5) + (-2*4) = 0
Let the oxidation number of P be x.
We know that oxidation number of Na= +1, O= -2
therefore, 3*1 + x+ 4* -2 = 0 (net charge on the molecule)
3 + x - 8 =0
x = +5
therefore, the answer is C)+5
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