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tiny-mole [99]
3 years ago
10

What is the oxidation number of phosphorus (P) in sodium phosphate (Na3PO4)?

Chemistry
2 answers:
joja [24]3 years ago
8 0
Na⁺¹₃P⁺⁵O⁻²₄

+1*3 + (+5) + (-2*4) = 0
marissa [1.9K]3 years ago
3 0

Let the oxidation number of P be x.  

We know that oxidation number of Na= +1, O= -2  

therefore,  3*1 + x+ 4* -2 = 0 (net charge on the molecule)  

3 + x - 8 =0  

x = +5  

therefore, the answer is C)+5

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The accepted value is 29.35. Which correctly describes this student's experimental data?
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Answer:

- Both accurate and precise.

Explanation:

The experimental data is characterized as the data that is generated through a specific test or measurement with the purpose of analysis or evaluation. As per the question, the minuteness of the given data(29.27, 29.32, and 29. 27)most aptly describes that the experimental data collected by the student possesses 'accuracy and precision' apt and specific. It would yield the most worthy and reliable conclusion.

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AgNO2+Na3PO4<br><br> Solve and predict if its a precipitate
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Read 2 more answers
Convert 533 cm/s to units of meters per minute. Show the unit analysis by dragging the conversion factors into the unit‑factor s
lukranit [14]

Answer:

319.8 m/min

Explanation:

533 cm/s

We can convert 533 cm/s to m/min by doing the following:

First, we shall convert 533 cm/s to m/s. This can be obtained as illustrated below:

Recall:

100 cm/s = 1 m/s

Therefore,

533 cm/s = 533 cm/s /100 cm/s × 1 m/s

533 cm/s = 5.33 m/s

Finally, we shall convert 5.33 m/s to m/min. This can be obtained as follow:

1 m/s = 60 m/min

Therefore,

5.33 m/s = 5.33 m/s / 1 m/s × 60 m/min

5.33 m/s = 319.8 m/min

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8 0
3 years ago
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