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Alexandra [31]
3 years ago
15

which statements about acceleration are true? check all that apply. a. the si units of acceleration are m/s2. b. for acceleratio

n, you must have a number, a unit, and a direction. c. to calculate acceleration, divide the change in speed by the change in time. d. the symbol for acceleration is .

Physics
2 answers:
Salsk061 [2.6K]3 years ago
6 0
<span>A is True:

</span>The formula for acceleration is:

Acceleration = \frac{Vf-Vi}{t}
Acceleration = \frac{Xm/s-Xm/s}{s} = Xm/s^{2}

Because the unit of velocity is m/s and the unit of time is second this is what happened:

\frac{m}{s} ÷\frac{s}{1}

\frac{m}{s} ÷X \frac{1}{s} = \frac{m}{s^{2}} 

B is True:

Acceleration is a vector quantity, so that means it should have both magnitude and direction. When given an acceleration, the sign usually indicates the direction. A negative value is a sign that it is decelerating and not accelerating. 

D could be true only if:

Your question is actually broken so we do not know the symbol you are showing. But in general, the symbol of acceleration is a letter "a" with an arrow on top. You can see in the picture attached to see the symbol I am referring to. 

C is not true because acceleration is the change in VELOCITY over time. Velocity and speed are different. 



tatiyna3 years ago
5 0

The first thing you should know is that acceleration is a vector, therefore, it has magnitude, and direction.

By definition, we have that the vector acceleration is given by:

a = \frac{dv}{dt}\\

Where,

dv/dt: derived from the velocity vector with respect to time,

Therefore, the units of the vector acceleration are:

a = \frac{\frac{m}{s}}{s}\\

a = \frac{m}{s^2}

The symbol of acceleration is:

a^{->}

Answer:

The statements about acceleration that are true are:

a. the si units of acceleration are m/s2.

b. for acceleration, you must have a number, a unit, and a direction.

d. the symbol for acceleration is (True, only if the symbol is the same as above)

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R_s=\left | \dfrac{n_1cos\theta_i-n_2cos\theta_t}{n_1cos\theta_i+n_2cos\theta_t} \right |^2\\R_p=\left | \dfrac{n_1cos\theta_t-n_2cos\theta_i}{n_1cos\theta_t+n_2cos\theta_i} \right |^2

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b) R_p=\left | \dfrac{\dfrac{\sqrt{7}}{3}-\dfrac{1.5}{\sqrt{2}}}{\dfrac{\sqrt{7}}{3}+\dfrac{1.5}{\sqrt{2}}} \right |^2

R_p = 0.085

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