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Alexandra [31]
3 years ago
15

which statements about acceleration are true? check all that apply. a. the si units of acceleration are m/s2. b. for acceleratio

n, you must have a number, a unit, and a direction. c. to calculate acceleration, divide the change in speed by the change in time. d. the symbol for acceleration is .

Physics
2 answers:
Salsk061 [2.6K]3 years ago
6 0
<span>A is True:

</span>The formula for acceleration is:

Acceleration = \frac{Vf-Vi}{t}
Acceleration = \frac{Xm/s-Xm/s}{s} = Xm/s^{2}

Because the unit of velocity is m/s and the unit of time is second this is what happened:

\frac{m}{s} ÷\frac{s}{1}

\frac{m}{s} ÷X \frac{1}{s} = \frac{m}{s^{2}} 

B is True:

Acceleration is a vector quantity, so that means it should have both magnitude and direction. When given an acceleration, the sign usually indicates the direction. A negative value is a sign that it is decelerating and not accelerating. 

D could be true only if:

Your question is actually broken so we do not know the symbol you are showing. But in general, the symbol of acceleration is a letter "a" with an arrow on top. You can see in the picture attached to see the symbol I am referring to. 

C is not true because acceleration is the change in VELOCITY over time. Velocity and speed are different. 



tatiyna3 years ago
5 0

The first thing you should know is that acceleration is a vector, therefore, it has magnitude, and direction.

By definition, we have that the vector acceleration is given by:

a = \frac{dv}{dt}\\

Where,

dv/dt: derived from the velocity vector with respect to time,

Therefore, the units of the vector acceleration are:

a = \frac{\frac{m}{s}}{s}\\

a = \frac{m}{s^2}

The symbol of acceleration is:

a^{->}

Answer:

The statements about acceleration that are true are:

a. the si units of acceleration are m/s2.

b. for acceleration, you must have a number, a unit, and a direction.

d. the symbol for acceleration is (True, only if the symbol is the same as above)

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kipiarov [429]
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lianna [129]

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4 years ago
A 20-gram bullet traveling at 250 m/s strikes a block of wood that weighs 2 kg. With what velocity will the block and bullet mov
Shkiper50 [21]

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the velocity of the bullet-wood system after the collision is 2.48 m/s

Explanation:

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mass of the bullet, m₀ = 20 g = 0.02 kg

velocity of the bullet, v₀ = 250 m/s

mass of the wood, m₁ = 2 kg

velocity of the wood, v₁ = 0

Let the velocity of the bullet-wood system after collision = v

Apply the principle of conservation of linear momentum to calculate the final velocity of the system;

Initial momentum = final momentum

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0.02 x 250  + 2 x 0    =    v(2  + 0.02)

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5 = 2.02v

v = 5/2.02

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Therefore, the velocity of the bullet-wood system after the collision is 2.48 m/s

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3 years ago
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