Car A has a mass of 2000 kg and is going 28 m/s east.
1 answer:
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Answer:
<em>The total potential (magnitude only) is 11045.45 V</em>
Explanation:
<u>Electric Potential </u>
The total electric potential at location A is the sum of all four individual potentials produced by the charges, including the sign since the potential is a scalar magnitude that can be computed by
Where k is the Coulomb's constant, q is the charge, and r is the distance from the charge. Let's find the potential of the rightmost charge:
The potential of the leftmost charge is exactly the same as the above because the charges and distances are identical
The potential of the topmost charge is almost equal to the above computed, is only different in the sign:
The bottom charge has double distance and the same charge, thus the potential's magnitude is half the others':
The total electric potential in A is
The total potential (magnitude only) is 11045.45 V
Answer:
c = 4,444.44
Explanation:
You have the following expression for the acceleration of the projectile:
(1)
s: distance to the ground of the projectile
To find the value of the constant c you use the following formula:
(2)
vo: initial velocity = 0 m/s
v: final speed = 200 m/s
Δs: distance traveled by the projectile = 3m - 1.5m = 1.5m
You replace the expression (1) into the expression (2):
You do the constant c in the last equation, then you replace the values of v, s and Δs: