Answer:
t = 5.4 s
Explanation:
from the question we are given :
height (s) = 20 m
mass of paint (Mp) = 4 kg
mass of nails (Mn) = 3 kg
acceleration due to gravity (g) = 9.8 m/s^{2}
- The net force accelerating the can of paint should be equal to the difference in weight of the can of paint and the can of nails.
weight of nails = mass of nails x g = 3 x 9.8 = 29.4 N
weight of paint = mass nails x g = 4 x 9.8 = 39.2 N
net force = 39.2 - 29.4 = 9.8 N
- net force = total mass x acceleration
9.8 = (3 +4) x a
a = 1.4 m/s^{2}
- from S = Ut + 0.5at^{2} we can get the time the carpenter has to catch the nails
where U is the initial velocity and is 0 since the can was initially at
rest
20 = (0 x t) + (0.5 x 1.4 x t^{2})
20 = 0.7 x t^{2}
t^{2} = 28.6
t = 5.4 s
The bigger molecule has more interactions and hence the higher b.p. CH3CH2OCH2CH3 is a bigger molecule than CH4 and CH3CH3, so has more dispersion forces. It also has dipole-dipole forces due to the polarised C-O bonds. CH3OH and CH3CH2OH have hydrogen bonds due to the very electronegative O atom bonded to the H atom
God bless
Answer:
Range will become 4 times of initial range
Explanation:
Let the velocity of projection is u
And angle at which projectile is projected is 
And acceleration due to gravity is 
So range of projectile is equal to 
........eqn 1
Now in second case it is given that velocity of launching is doubled
So new velocity 
So new range will be equal to 
.....eqn 2
Now dividing eqn 2 by eqn 1
So if we double the initial launch speed then range will become 4 times
