Answer:
THE HEAT REQUIRED TO CHANGE 2 KG OF ETHANOL FROM 26 °C TO THE BOILING POINT AND TO VAPOR AT THAT TEMPERATURE IS 1965.175 KJ.
Explanation:
Boiling point of ethanol = 78.29 °C = 78.29 + 273 K = 351.29 K
Mass = 2 kg = 2000 g
Final temp. = 26.0 °C = 26 + 273 K= 299 K
Change in temperature = (78.29 - 26) °C = 52.29 °C
1. Heat required to raise the temperature from 26 °C to the boiling point?
Heat = mass * specific heat * change in temperature
Heat = 2000 * 2.44 * 52.29
Heat = 255 175.2 J
2. Heat required to change the liquid to vapor at that temperature?
Heat = mass * enthalphy of vaporization
Heat = 2000 * 855
Heat =1 710000 J
The total heat required to raise the temperature of 2 kg of ethanol from 26 °C to the boiling point and then to change the liquid to vapor at that temperature will be:
Heat = mcT + m Lv
Heat = 255 175.2 J + 1710000 J
Heat = 1965175.2 J
Heat = 1965.175 kJ of heat.
Lemonade is an example of a solution.
A solution is a combination of two or more substances that form a single phase.
Lemonade consists of several substances that are homogeneously combined in the solution.
The presence of lemon juice makes the lemonade to have a yellow color but the presence of sugar makes it sweet among other components of the solution mixture.
Learn more: brainly.com/question/5139963
The concentration by mass means that the mass of solute in a given amount of solution. So for the a), the concentration should be 17/(17+183)*100%=8.5%. For b), the concentration should be 30/(30+300)*100%=9.09%.
