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Tasya [4]
4 years ago
15

PLEASE HELP I NEED THIS BY 11:00 P.M

Physics
1 answer:
dem82 [27]4 years ago
4 0

Answer:

no values are given I mean numbers

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Difference between regular and irregular object.​
DaniilM [7]
<h2><em>Answer:</em></h2><h2><em>Regular </em><em>object</em></h2>
  • <em>Those </em><em>substance </em><em>which </em><em>have </em><em>fixed </em><em>geometrical </em><em>shape </em><em>are </em><em>called </em><em>regular </em><em>object.</em>
  • <em>For </em><em>example</em><em>:</em><em> </em><em>books,</em><em>pencils,</em><em> </em><em>basketball</em><em> </em><em>etc.</em>
<h2><em>Irregular </em><em>object</em></h2>
  • <em>Those </em><em>substance </em><em>which </em><em>do </em><em>not </em><em>have </em><em>geometrical</em><em> </em><em>shape </em><em>are </em><em>called </em><em>irregular</em><em> </em><em>object</em><em>.</em>
  • <em>For </em><em>example:</em><em> </em><em>a </em><em>piece </em><em>of </em><em>stone,</em><em>a </em><em>broken </em><em>piece </em><em>of </em><em>brick,</em><em>leaf </em><em>etc.</em>

<em>Hope </em><em>this </em><em>helps.</em><em>.</em><em>.</em><em>.</em>

<em>Good </em><em>luck</em><em> on</em><em> your</em><em> assignment</em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em>

5 0
4 years ago
Chapter 38, Problem 001
Norma-Jean [14]

Answer:

a) \lambda=2.95x10^{-6}m

b) infrared region

Explanation:

Photon energy is the "energy carried by a single photon. This amount of energy is directly proportional to the photon's electromagnetic frequency and is inversely proportional to the wavelength. If we have higher the photon's frequency then we have higher its energy. Equivalently, with longer the photon's wavelength, we have lower energy".

Part a

Is provide that the smallest amount of energy that is needed to dissociate a molecule of a material on this case 0.42eV. We know that the energy of the photon is equal to:

E=hf

Where h is the Planck's Constant. By the other hand the know that c=f\lambda and if we solve for f we have:

f=\frac{c}{\lambda}

If we replace the last equation into the E formula we got:

E=h\frac{c}{\lambda}

And if we solve for \lambda we got:

\lambda =\frac{hc}{E}

Using the value of the constant h=4.136x10^{-15} eVs we have this:

\lambda=\frac{4.136x10^{15}eVs (3x10^8 \frac{m}{s})}{0.42eV}=2.95x10^{-6}m

\lambda=2.95x10^{-6}m

Part b

If we see the figure attached, with the red arrow, the value for the wavelenght obtained from part a) is on the infrared region, since is in the order of 10^{-6}m

4 0
3 years ago
How much kinetic energy does an 80 kg man have while running at 3 m/s?
Soloha48 [4]

Hello!

\large\boxed{KE = 360 J}

Use the equation KE = 1/2mv² to solve for the kinetic energy of the man.

We are given the mass and velocity, so plug these values into the equation:

KE = 1/2(80)(3²)

KE = 1/2(720)

KE = 360 J

7 0
3 years ago
a body starts from rest and moving under uniform acceleration of 4 metre per second square travel half of its total path during
lakkis [162]

Answer:

t = 3.414 s

s = 23.3 m

Explanation:

Let t be the total time of motion

Let s be the total distance of motion

s - s/2 = ½at² - ½a(t - 1²) = ½a(t² - (t - 1)²)

s/2 = ½a(t² - (t² - 2t + 1)) = ½a(t² - t² + 2t - 1)

s = a(2t - 1)

s = 4(2t - 1)

s = 8t - 4

8t - 4 = ½4t²

8t - 4 = 2t²

0 = 2t² - 8t + 4

0 = t² - 4t + 2

t = (4 ±√(4² - 4(1)(2))) / 2 = (4 ± √8)/2 = 2 ± √2

t = 3.414 s

or

t = 0.5857... s which we ignore because it does not have a full last second.

s = ½(4)3.414² = 23.3137... 23.3 m

5 0
3 years ago
check the file.........................................................................................................
White raven [17]

What is meant by the number of complete oscillation made by an oscillating body in 10 seconds is 500 complete oscillations is that the  frequency of the oscillating body is 50Hz

<h3>What is frequency?</h3>

Frequency of an oscillating body can be defined as the number of complete oscillations per unit time

Frequency is measured in hertz (Hz).

Also, the frequency of 1Hz is one oscillation per second.

frequency = number of oscillations/ time taken

frequency = 500/10 = 50 Hz

Thus, what is meant by the number of complete oscillation made by an oscillating body in 10 seconds is 500 complete oscillations is that the  frequency of the oscillating body is 50Hz

Learn more about frequency here:

brainly.com/question/1199084

#SPJ1

6 0
2 years ago
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